Answer:
Only option B is correct, i.e. all real values of x except x = 2.
Step-by-step explanation:
Given the functions are C(x) = 5/(x-2) and D(x) = (x+3)
Finding (C·D)(x) :-
(C·D)(x) = C(x) * D(x)
(C·D)(x) = 5/(x-2) * (x+3)
(C·D)(x) = 5(x+3) / (x-2)
(C·D)(x) = (5x+15) / (x-2)
Let y(x) = (C·D)(x) = (5x+15) / (x-2)
According to definition of functions, the rational functions are defined for all Real values except the one at which denominator is zero.
It means domain will be all Real values except (x-2)≠0 or x≠2.
Hence, only option B is correct, i.e. all real values of x except x = 2.
Answer:576
Step-by-step explanation:
Answer:
if you're looking for x its -13
Answer:
The theoretical probability of getting a 5 is 16.6% or near 20%. Or 1 of 6
the theoretical probability of getting a 0 is 0% because there is no 0.
Step-by-step explanation:
52
- is prime? No
- is multiple of 3? No
continue
53
- is prime? Yes
continue
54
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? No
continue
55
- is prime? No
- is multiple of 3? No
continue
56
- is prime? No
- is multiple of 3? No
continue
57
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? No
continue
58
- is prime? No
- is multiple of 3? No
continue
59
- is prime? Yes
continue
60
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? Yes
Therefore 60 is the answer, as it fits all the conditions
Simple trial and error.