Simple pythagorus theorem with the equation a^2=b^2+c^2
To find AC, (2^2)+(3^2)=4+9=13
AC=the square root of 13
Answer:
Step-by-step explanation:
Answer: it's B
Step-by-step explanation:
you just have to use the AG and work backwards to find AD
Answer:
(1,1) x=1 y=1
Step-by-step explanation:
Answer:
x=3/7 and x= 3
Step-by-step explanation:
First simplify:
-14 x^2 +48x -18
divide everything by -2
-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)
-2 (x^2 -24x +63)
-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21
-2 [(x-3/7)(x-21/7)]
-2 [(7x-3)(x-3)]
Hence, the zeroes are 3/7 and 3
Hope this helps!
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