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3 years ago

Help please!! I’m confused on this question. Thank you!!!

Mathematics

2 answers:

slava [35]3 years ago

8 0

Answer:

it's an acute angle

Step-by-step explanation:

if its larger than 90⁰ then it's obtuse however if it's smaller than 90⁰ it's acute

myrzilka [38]3 years ago

6 0

Answer:

Im pretty sure that is an obtuse angle

Step-by-step explanation:

Hope that helps

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Number six on the page

Mekhanik [1.2K]

A square has the same length on all of it's sides. The area of a square is side times side. So it's 2.2×2.2=?

7 0

3 years ago

I need help please !!!

juin [17]

Answer:

f = 12(s - 35).

Step-by-step explanation:

The number of miles per hour he was over the limit = s - 35.

So his fine f is:

f = 12(s - 35).

6 0

3 years ago

A quadrilateral whose consecutive sides measure 15, 18,15, and 18

anastassius [24]

Answer:

its a rectangle

Step-by-step explanation:

how to explain this

6 0

3 years ago

Step 2: Radii OK and NL are perpendicular to OM because of the radius-tangent theorem. By definition of perpendicular, angles KO

solong [7]

Answer:

Angle Angle Angle (AAA) property

Step-by-step explanation:

A right angled triangle is a triangle that has one of its angles to equal $90^{0}$ . It could be in the form of an isosceles triangle or an acute angled triangle.

The given question compares the congruence properties of two triangles, KOM and LNM.

Thus,

<KOM = <LNM (right angle theorem)

<LMN = <KMO (common angles to both triangles)

⇒ <OKM = <NLM (property of a triangle i.e sum of angle in a triangle is $180^{0}$ )

ΔKOM = ΔLNM (congruence property)

Therefore, by angle angle angle (AAA) congruence property, the two triangles are similar.

7 0

3 years ago

One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

3 years ago