Answer:
2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.
Explanation:
Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below
litres
litres
Also the quantity of alcohol is given as
Now the equation is as

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.
Answer:
variable: not consistent or having a fixed pattern; liable to change.
Explanation:
The answer to your question is an Egg
First one is yes second one is no :)
Answer:

Explanation:

A hydroxide of a metal is a base.

B is wrong. HCl is an acid.
C is wrong. NaCl is a salt.
D is wrong. Water is neutral.