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3 years ago

What is the pH of a 3.5 x 10-5 M solution of HCl?

Chemistry

1 answer:

kolezko [41]3 years ago

4 0

Answer:

4.46

Explanation:

Applying,

pH = -log(H⁺)....................... Equation 1

Where H⁺ = Hydrogen ion concentration of HCl solution

From the question,

Given: H⁺ = 3.5×10⁻⁵ M

Substitute these values into equation 1

pH = -log(3.5×10⁻⁵)

pH = 4.46

Hence the pH of HCl solution is 4.46

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A 35.0-ml sample of 0.20 m lioh is titrated with 0.25 m hcl. What is the ph of the solution after 23.0 ml of hcl have been added

kiruha [24]

<h3>Answer;</h3>

pH = 12.33

<h3>Explanation;</h3>

The equation of reaction is :

LiOH(aq) + HCl(aq) --> LiCl(aq) + H2O(l)

Reactants left after the titrant is added;

Total Moles LiOH;

= 0.035L LiOH × (0.2moles/L)

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Reacting amount of moles of LiOH;

= 0.0575 moles HCl *(1mole LiOH/1moles HCl)

=0.00575 moles LiOH (reacted)

Moles of LiOH left;

= 0.007moles total - 0.00575moles that react

= .00125 moles of LiOH (left)

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0.00125moles LiOH *(moles/0.058L) = 0.02155M of LiOH

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pOH = -log(0.02155)

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pH = 14 - 1.67

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