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Luda [366]
3 years ago
12

What is the pH of a 3.5 x 10-5 M solution of HCl?

Chemistry
1 answer:
kolezko [41]3 years ago
4 0

Answer:

4.46

Explanation:

Applying,

pH = -log(H⁺)....................... Equation 1

Where H⁺ = Hydrogen ion concentration of HCl solution

From the question,

Given: H⁺ =  3.5×10⁻⁵ M

Substitute these values into equation 1

pH = -log(3.5×10⁻⁵)

pH = 4.46

Hence the pH of HCl solution is 4.46

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If phosphorous has 5 valence electrons, how many does sulfur have?
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Explanation:

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Compare which element would have larger first ionization energy: an alkali metal in Period 2 or an alkali metal in Period 4?
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Answer:

An alkali metal present in period 2 have larger first ionization energy.

Explanation:

Ionization energy:

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Trend along period:

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Trend along group:

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As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.  Thus alkali metal present in period 2 have larger ionization energy because of more nuclear attraction as compared to the alkali metal present in period 4.

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