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kipiarov [429]
3 years ago
10

Which of the following statement is true?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
4 0

Answer:

a. The resonance effect of the hydroxyl group stabilizes the anionic intermediate

Explanation:

The resonance effect stabilizes the the charge through the delocalization of the pi bonds. The resonance stabilization mainly occurs in the conjugated pi systems.

For example, phenol forms a strong hydrogen bonds than the nonaromatic alcohols as the $O_2-H_2$ dipole present in the hydroxyl group is being stabilized by the presence of the aromatic ring of phenol.

Thus the resonance effect of the hydroxyl group stabilizes the anionic intermediate.

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A 3.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
andrew-mc [135]

Answer: The molecular formula for the given organic compound X is C_6H_{8}O_7

Explanation:

We are given:

Mass of CO_2=4.13g

Mass of H_2O=1.13g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 4.13 g of carbon dioxide, =\frac{12}{44}\times 4.13=1.13g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 1.13 g of water, \frac{2}{18}\times 1.13=0.125g of hydrogen will be contained.

Mass of oxygen in the compound = (3.00) - (1.13+ 0.125) = 1.75 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.13g}{12g/mole}=0.094moles

Moles of Hydrogen =\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.125g}{1g/mole}=0.125moles

Moles of Oxygen =\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.75g}{16g/mole}=0.109moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles

For Carbon = \frac{0.094}{0.094}=1

For Hydrogen = \frac{0.125}{0.094}=1.33

For Oxygen = \frac{0.109}{0.094}=1.16

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1: 1.33: 1.16

Converting them into whole number ratios by multiplying by 6:

The ratio of C : H : O = 6: 8: 7

Hence, the empirical formula for the given compound is C_6H_8O_7

Empirical mass = 6\times 12+8\times 1+7\times 16=192g

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

Putting values in above equation, we get:

n=\frac{192g/mol}{192g/mol}=1

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_6H_8O_7\times 1=C_6H_{8}O_7

Thus molecular formula for the given organic compound X is C_6H_{8}O_7

7 0
3 years ago
A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O
stepan [7]

Explanation:

Cr=35.880/51=0.73≈0.7

P=21.076/31=0.67≈0.7

O=43.543/16=2.71

Divide each by 0.7 u get

Cr=1 ,P =1, O=4

Empirical formula is CrPO4

3 0
3 years ago
What does all flexible objects have in common
Musya8 [376]
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6 0
3 years ago
Ms. Sullivan's class is designing a miniature roller coaster. After first setting it up, they find that it didn't have enough sp
Archy [21]

Letter D.

The scarier the better, and many people like loops

4 0
3 years ago
Calculate the mass of copper that could be made from 4.0g of copper oxide
Licemer1 [7]

The mass of copper that will be produced from copper oxide is determined as 3.19 g.

<h3>Mass of copper produced from copper oxide</h3>

The mass of copper that will be produced from copper oxide is calculated as follows;

2Cu + O₂  -----> 2CuO

2          1             2

2(63.5) ------------ 2(79.5)

x ---------------------- 4 g

x = (4 x 2 x 63.5)/(2 x 79.5)

x = 3.19 g

Thus, the mass of copper that will be produced from copper oxide is determined as 3.19 g.

Learn more about copper here: brainly.com/question/24856041

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7 0
2 years ago
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