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goldenfox [79]
3 years ago
13

What is the mass in grams of 3x10 atoms of helium

Chemistry
1 answer:
Zepler [3.9K]3 years ago
3 0

Answer:

here

Explanation:

What is the total mass of $$3.01 x 10^23$$ atoms of helium gas?

✓ Well $$"Avogadro's number"$$ of helium atoms has a mass of $$4.0*g$$. Explanation: And $$"Avogadro's number"$$

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A high altitude burst 
 A detonation of a nuclear explosive above 100,000 feet of altitude is called
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Which of the following is an advance in technology that has helped us to increase environmental quality?
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Consider a hypothetical metal that has a density of 11.6 g/cm3, an atomic weight of 157.6 g/mol, and an atomic radius of 0.127 n
Liula [17]

Answer:

APF(atomic packing factor)=0.31736

Explanation:

From the question we are told that

Density of metal \rho=11.6 g/cm3

Atomic weight of W=157.6 g/mol

Atomic radius of r= 0.127 nm

Lattice parameters=>x=0.523nm  and y=0.330 nm

Generally the equation for atomic packing factor is mathematically given as

APF(atomic packing factor)=\frac{Spere's\ volume}{unit\ cell\ volume}

APF(atomic packing factor)=\frac{N*VN}{VC}

Generally the equation for number of atoms N is mathematically given as

N=\frac{\rho }{atomic raduis*Avacados constant}

N=\frac{11.6 }{0.127*10^{-9}*6.02214086*10^{23} mol-1}

N=4

Therefore APF(atomic packing factor)

APF(atomic packing factor)=\frac{N*VN}{VC}

APF(atomic packing factor)=\frac{4*\frac{4}{3} \pi (0.127)^3}{(0.523)^2 *0.330}

APF(atomic packing factor)=0.31736

7 0
3 years ago
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