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AlladinOne [14]
3 years ago
14

HELPPPP 7th GRADE SCIENCE PROBLEM ABOUT KINETIC ENERGY OF ATOMS TEMPERATURE

Chemistry
1 answer:
patriot [66]3 years ago
6 0
1 and 4 are the correct answers
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whate is night blindness ? write its two symptoms

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if i add water to 100 mL of a 0.75 M NaOH solution un til the final volume is 165mL what will the molarity of the diluted soluti
ehidna [41]
Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
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A
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B. because if you add ice to tea and water it decreases the temperature as the ice melts
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The best solution for the problem of pollution by man-made technologies A. cannot involve anyone who is not a technology expert
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is likely to come from collaborative efforts by technology experts and experts on pollution.

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Synthesis of the activated form of acetate (acetyl‑CoA) is carried out in an ATP‑dependent process. Acetate+CoA+ATP⟶Acetyl−CoA+A
murzikaleks [220]

Answer:

\Delta G^{o} of the reaction is 1.7 kJ/mol.

Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.

Explanation:

The synthesis of acetyl CoA is as follows.

Form the given data,

Acetyl\rightarrow CoA \rightarrow Acetate+ CoA; \Delta G_{1}^{o}=-32.2\,kJ.mol^{-1}\\

ATP\rightarrow AMP+PP_{i};\Delta G_{2}^{o}=-30.5kJ.mol^{-1}

Total the above two steps we get,

Acetate+CoA+ATP\rightarrow Acetyl-CoA+AMP+PP_{i}

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Therefore, \Delta G^{o} of the reaction is 1.7 kJ/mol.

According to the Lechatelier's principle, a system at equilibrium always shows a tendency to regain the state of equilibrium., if equilibrium disturbed by an external factor only.

The enzyme inorganic pyrophosphotase catalyze the reaction.

The enzyme removes the ppi , one of the product in acetyl -CoA  reaction.

This would disturb the equilibrium therefore, system try to regain the state of equilibrium. And the equilibrium shifted to the right side.

Therefore, Hydrolysis of the pyrophosphate shifts the equilibrium of the reaction to the right, making the formation of acetyl-CoA energetically more favorable.

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