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3 years ago

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I need help with this

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Ulleksa [173]3 years ago

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No, tahts the answer

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

Simplify the expression 3 (5x)

Dovator [93]

Answer:

15x

Step-by-step explanation:

i just know (100% positive)

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3 years ago

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Blake watched of a movie on Friday, of the movie

xeze [42]

Answer:

1/3

Step-by-step explanation:Because he split the movie into 3 parts

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3 years ago

Im giving extra points and brainliest

Veseljchak [2.6K]

Answer: the c

Step-by-step explanation:

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3 years ago

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Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as hi

azamat

Complete question is;

Roger is building a storage shed with wood blocks that are in the shape of cubic prisms. Can he build a shed that is twice as high as it is wide?

A. Yes. For every block of width, he could build two blocks high.

B. Yes. He could use half as many blocks for the height as the width.

C. There is no way to determine if he can do this.

D. No, it is not possible to do this

Answer:

A. Yes. For every block of width, he could build two blocks high.

Step-by-step explanation:

We are told that the wood blocks are in the shape of cubic prisms.

Now, cube shapes means that all sides are equal.

Now, if he divides the cube into 2, he can use one have to add to the top to make the height double since the sides are equal.

Thus, the height will now be twice a side of the cubic prism.

Thus, he can build a shed twice as high as its width.

6 0

3 years ago

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