2 years ago

2 Which is a factor of x² + 5x – 24? 1) (x + 4)2) (x - 4) 3) (x + 3) 4) (x – 3)

Mathematics

1 answer:

insens350 [35]2 years ago

3 0

Answer:

(X+3)

Step-by-step explanation:

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Verify that the roots of 5x²- 6x -2 = 0 are <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%20%2B%20%5Csqrt%7B19%7D%20%7D%7B5%7D%2

Mice21 [21]

Answer:

Proof below.

Step-by-step explanation:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Given quadratic equation:

$5x^2-6x-2=0$

Define the variables:

a = 5
b = -6
c = -2

Substitute the defined variables into the quadratic formula and solve for x:

$\implies x=\dfrac{-(-6) \pm \sqrt{(-6)^2-4(5)(-2)}}{2(5)}$

$\implies x=\dfrac{6 \pm \sqrt{36+40}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{76}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4 \cdot 19}}{10}$

$\implies x=\dfrac{6 \pm \sqrt{4}\sqrt{19}}{10}$

$\implies x=\dfrac{6 \pm2\sqrt{19}}{10}$

$\implies x=\dfrac{3 \pm \sqrt{19}}{5}$

Therefore, the exact solutions to the given quadratic equation are:

$x=\dfrac{3 + \sqrt{19}}{5} \:\textsf{ and }\:x=\dfrac{3 - \sqrt{19}}{5}$

Learn more about the quadratic formula here:

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3 years ago

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Vesnalui [34]

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2 years ago

Find the coordinates of the other endpoint of the segment, given its midpoint and one endpoint. (Hint: Let (x,y) be the unkno

melomori [17]

Mid point formula =
(x1/2+x2/2, y1/2+y2/2)

x=
x+0 = 8
/2
x+0 = 8 x 2
x = 16

y=
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/2
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y=2+2
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(16,4)

(In this case, the midpoint (x ,y) will be represent as the answer)

7 0

3 years ago

2 Which is a factor of x² + 5x – 24? 1) (x + 4)2) (x - 4) 3) (x + 3) 4) (x – 3)​

2 Which is a factor of x² + 5x – 24? 1) (x + 4)2) (x - 4) 3) (x + 3) 4) (x – 3)