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d1i1m1o1n [39]
3 years ago
13

What is shown by the pattern of iron filings around these two magnets?

Physics
2 answers:
nadya68 [22]3 years ago
8 0

Answer:c

Explanation:

muminat3 years ago
3 0

Answer:

c

Explanation:

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Will someone please help me I only have a couple mins left.
Artyom0805 [142]

Answer:

Okay!! What's the question?

Explanation:

Maybe I can help!

5 0
3 years ago
A passenger is running inside a stationary train with some speed and looks at the person standing on the platform. Describe the
Lubov Fominskaja [6]

Answer:

Doppler effect

Explanation:

this means that at one point when the person running is close to the observer it will appear to run fast but slower as he moves away from the observer

4 0
2 years ago
In a hot water heating system, room temperature is controlled by a device called a
erik [133]
<h3><u>Answer</u>;</h3>

Thermostat

<h3><u>Explanation;</u></h3>
  • A thermostat is a device that exerts control by switching heating or cooling devices on or off, or by regulating the flow of a heat transfer fluid as needed, to maintain the correct temperature.
  • Thermostat automatically regulates temperature, or that activates a device when the temperature reaches a certain point.
4 0
3 years ago
Two charges 5 c and 15 c are seperated by 10 cm. what is the electric force between them?
icang [17]

Answer:

6.75×10^13N

Explanation:

The electric force between the charges can be determined using coulombs law which states that 'the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of their distance between them.

Mathematically, F = kq1q2/r² where;

q1 and q2 are the charges

r is the distance between the charges

F is the force of attraction

k is the coulombs constant

Given q1 = 5C q2 = 15C r = 10cm = 0.1m k = 9×10^9Nm²/C²

Substituting the given values in the formula we have;

F =9×10^9×5×15/0.1²

F = 6.75×10^11/0.01

F = 6.75×10^13N

Therefore the electric force between them is 6.75×10^13N

8 0
3 years ago
a foul ball is hit into the stands at a baseball game. the ball rises to a height of 38 meters and is caught on its way down by
lisov135 [29]

The velocity of the ball when it was caught is 12.52 m/s.

<em>"Your question is not complete it seems to be missing the following, information"</em>,

find the velocity of the ball when it was caught.

The given parameters;

maximum height above the ground reached by the ball, H = 38 m

height above the ground where the ball was caught, h = 30 m

The height traveled by the ball when it was caught is calculated as follows;

y = H - h

y = 38 - 30 = 8 m

The velocity of the ball when it was caught is calculated as;

v_f^2 = v_0 + 2gh\\\\v_f^2 = 0 + (2\times 9.8 \times 8)\\\\v_f^2 = 156.8\\\\v_f = \sqrt{156.8} \\\\v_f = 12.52 \ m/s

Thus, the velocity of the ball when it was caught is 12.52 m/s.

Learn more here: brainly.com/question/14582703

4 0
3 years ago
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