Answer:
5878 kJ/mol
Explanation:
According to the law of conservation of energy, the sum of the heat released by the combustion and the heat absorbed by the calorimeter is zero.
Qcomb + Qcal = 0
Qcomb = -Qcal [1]
The heat absorbed by the calorimeter (Qcal) can be calculated using the following expression:
Qcal = Ccal . ΔT = 3.640 kJ/°C × 19.35°C = 70.43 kJ
where,
Ccal is the heat capacity of the calorimeter
ΔT is the difference in temperature
From [1],
Qcomb = - 70.43 kJ
Since this heat is measured at constant pressure, the molar enthalpy of combustion of cymene is:
The ratio is 1.07 : 0.128 : 0.106.
What is N/P/K ratio ?
These three numbers form what is called the fertilizer's N-P-K ratio — the proportion of three plant nutrients in order: nitrogen (N), phosphorus (P) and potassium (K). The product's N-P-K numbers reflect each nutrient's percentage by weight.
Given, mass ratio of (Molar mass of N2 =28; Molar mass of PO=78; Molar mass of K2O)=94) is 30/10/10
Therefore the ratio is : 30/28 : 10/78 : 10/94 = 1.07 : 0.128 : 0.106
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The volume of chlorine required is 7.71 L.
The reaction between phosphorus and chlorine is:
2P + 5Cl₂→ 5PCl₅
Therefore, 2 moles of P requires 5 moles of chlorine to react with it.
Given mass of P =3.39 g
Molar mass of P=30.97 g/mol
No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles
2 moles of P requires 5 moles of chlorine
0.109 moles of P will require 0.109 x 5/2 = 0.2725 moles of chlorine
According to ideal gas equation
PV=nRT
2.04 x V = 0.2725 x 0.0821 x 703
V = 0.2725 x 0.0821 x 703 / 2.04
V = 7.71L
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Answer:- 27.7 grams of 
are produced.
Solution:- The balanced equation is:
let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.
Molar mass of ![Pb(NO_3)_2 = 207.2+2(14.01)+6(16) = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2](https://tex.z-dn.net/?f=Pb%28NO_3%29_2%20%3D%20207.2%2B2%2814.01%29%2B6%2816%29%20%20%3D%20331.22%20gram%20per%20mol%3C%2Fp%3E%3Cp%3Emolar%20mass%20of%20NaI%20%3D%2022.99%2B126.90%20%3D%20149.89%20gram%20per%20mol%3C%2Fp%3E%3Cp%3EMolar%20mass%20of%20%5Btex%5DPbI_2)
= 207.2+2(126.90) = 461 gram per mol
let's do the calculations for the grams of the product for the given grams of each of the reactant:
= 
= 
From above calculations, NaI gives least amount of , so the answer is, 27.7 g of are produced.
