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Tomtit [17]
1 year ago
9

What will be the ph of a buffer solution containing an acid of pka 7. 5, with an acid concentration exactly one fourth of that o

f the conjugate base?
Chemistry
1 answer:
Over [174]1 year ago
8 0

8.1  will be the pH of a buffer solution containing an acid of pka 7. 5, with an acid concentration exactly one-fourth of that of the conjugate base.

In chemistry, the pH scale is used to define the acidity or basicity of an aqueous solution. Historically, pH stood for the "potential of hydrogen." The pH values of acidic solutions are typically lower than those of basic or alkaline solutions.

A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.

A weak base and its salt are combined with a strong acid to create a basic buffer, which has an acidic pH. the aqueous mixture of ammonium hydroxide and ammonium chloride, both in equal concentrations.

To know more about pH refer to:  

brainly.com/question/8676275

#SPJ4

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Find the molarity of a solution made by dissolving 12.5 g sodium carbonate in 500.0 mL total solution
Over [174]

Answer:

The molarity of a solution is "25 M".

Explanation:

The given values are:

Moles of solute,

= 12.5 g

Volume of solution,

= 500 mL

i.e.,

= 0.5 L

Now,

The molarity will be:

=  \frac{Number \ of \ moles \ of \ solute}{Volume \ of \ solution}

On substituting the values, we get

=  \frac{12.5}{0.5}

=  25 \ M

3 0
2 years ago
The A-36 steel pipe has a 6061-T6 aluminum core. It is subjected to a tensile force of 200 kN. Determine the average normal stre
rodikova [14]

Answer:

In the steel: 815 kPa

In the aluminum: 270 kPa

Explanation:

The steel pipe will have a section of:

A1 = π/4 * (D^2 - d^2)

A1 = π/4 * (0.8^2 - 0.7^2) = 0.1178 m^2

The aluminum core:

A2 = π/4 * d^2

A2 = π/4 * 0.7^2 = 0.3848 m^2

The parts will have a certain stiffness:

k = E * A/l

We don't know their length, so we can consider this as stiffness per unit of length

k = E * A

For the steel pipe:

E = 210 GPa (for steel)

k1 = 210*10^9 * 0.1178 = 2.47*10^10 N

For the aluminum:

E = 70 GPa

k2 = 70*10^9 * 0.3848 = 2.69*10^10 N

Hooke's law,

Δd = f / k

Since we are using stiffness per unit of length we use stretching per unit of length,

ε = f / k

When the force is distributed between both materials will stretch the same length,

f = f1 + f2

f1 / k1 = f2/ k2

Replacing:

f1 = f - f2

(f - f2) / k1 = f2 / k2

f/k1 - f2/k1 = f2/k2

f/k1 = f2 * (1/k2 + 1/k1)

f2 = (f/k1) / (1/k2 + 1/k1)

f2 = (200000/2.47*10^10) / (1/2.69*10^10 + 1/2.47*10^10) = 104000 N = 104 KN

f1 = 200 - 104 = 96 kN

Then we calculate the stresses:

σ1 = f1/A1 = 96000 / 0.1178 = 815000 Pa = 815 kPa

σ2 = f2/A2 = 104000 / 0.3848 = 270000 Pa = 270 kPa

5 0
3 years ago
In a nuclear reaction, the parent element is always radioactive.
Serga [27]
Hydrogen to be more precise protium which is an isotope of hydrogen containing one proton and one electron. It is considered to be very stable which explains it's abundance everywhere. However under extreme conditions like in the sun, it undergoes nuclear fusion to form helium. So in conclusion, under normal circumstances Protium is considered to be very stable however under extreme circumstances it is radioactive. Does that answer your question?

7 0
3 years ago
If a chemist has 17.8 moles of N2H4O3, what is the mass of the sample?<br><br> show work plz
harkovskaia [24]

(\frac{17.8mole}{1} )( \frac{66grams}{1mole} ) \:  \:  \:  \:  17.8 \times 66 = 1.17 \times  {10}^{3} grams
the way that you get 66 is by adding he atomic mass unit of each atom in the formula. so N2 is 14 + 14 H4 is 1 * 4 and 03 is 16 * 3
4 0
2 years ago
A student dissolves 0.0688 mol of sodium hydroxide in water to make a 0.250 L solution. What is the molarity of the solution?
den301095 [7]
Number of moles = 0.0688 moles of NaoH

volume = 0.250 L

Molarity = moles of solute / volume ( L )

M = 0.0688 / 0.250

M = 0.28 M

Answer B
7 0
3 years ago
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