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Tomtit [17]
1 year ago
9

What will be the ph of a buffer solution containing an acid of pka 7. 5, with an acid concentration exactly one fourth of that o

f the conjugate base?
Chemistry
1 answer:
Over [174]1 year ago
8 0

8.1  will be the pH of a buffer solution containing an acid of pka 7. 5, with an acid concentration exactly one-fourth of that of the conjugate base.

In chemistry, the pH scale is used to define the acidity or basicity of an aqueous solution. Historically, pH stood for the "potential of hydrogen." The pH values of acidic solutions are typically lower than those of basic or alkaline solutions.

A weak acid and the conjugate base of the weak acid, or a weak base and the conjugate acid of the weak base, are combined to form the buffer solution, a water-based solvent solution. They withstand being diluted or having modest amounts of acid or alkali added to them without changing their pH.

A weak base and its salt are combined with a strong acid to create a basic buffer, which has an acidic pH. the aqueous mixture of ammonium hydroxide and ammonium chloride, both in equal concentrations.

To know more about pH refer to:  

brainly.com/question/8676275

#SPJ4

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Which of the following would be expected to have the highest viscosity? CH3CH2OH, HOCH2OH, CH3CH2CH3
zaharov [31]

Answer: Out of the given options HOCH_{2}OH is expected to have the highest viscosity.

Explanation:

The resistance occurred in the flow of a liquid substance is called viscosity.

More stronger is the intermolecular forces present in a substance more will be its resistance in its flow. Hence, more will be its viscosity.

For example,  HOCH_{2}OH has strong intermolecular hydrogen bonding than the one's present in CH_{3}CH_{2}OH and CH_{3}CH_{2}CH_{3}. This is because two-OH groups are present over here.

Thus, we can conclude that out of the given options HOCH_{2}OH is expected to have the highest viscosity.

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A cough syrup contains 5.0% ethyl alcohol, c2h5oh, by mass. if the density of the solution is 0.9928 g/ml, determine the molarit
WARRIOR [948]
To answer the question above, let us a basis of the 1000 mL or 1 L. 
                 volume = (0.9928 g/mL)(1000mL) = 992.8 g
Then, determine the mass of the alcohol by multiplying the total mass by the decimal equivalent of 5%. 
               mass of alcohol = 0.05(992.8 g) = 49.64 g
Then, determine the number of moles of ethyl alcohol by dividing the mass of alcohol by the molar mass (46 g/mol). 
                       n = 49.64 g/ (46 g/mol) = 1.08 mol
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