Ask question

Ask question

All categories

3 years ago

10

Match each chemical reaction with the type of reaction that best describes it.

1 answer:

r-ruslan [8.4K]3 years ago

8 0

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂ (single displacement)

Ca + Br₂ → CaBr₂ (synthesis)

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O (combustion)

2 NaCl → 2 Na + Cl₂ (decomposition)

FeS + 2 HCl → FeCl₂ + H₂S (double displacement)

single displacement - is a chemical reaction of the following type: A + BC → AC + B

double displacement - is a chemical reaction of the following type: AB + CD → AC + BD

synthesis - the chemical product is obtained by combining in a synthesis the constituent elements

combustion - usually a exothermic reaction of a particular compound with oxygen

decomposition - degradation of a compound in simpler elements

You might be interested in

Is smoke a compound or a mixture? explain your answer.

goldfiish [28.3K]

Explanation:

hope it is helpful to you ☺️

8 0

3 years ago

How do scientists test for a substance’s flammability in a substance

saveliy_v [14]

Answer:

Determining flammability can be as simple as holding a sample of the substance over a match. If it burns, it is flammable, leading to additional experiments to find more properties. Measuring the heat given off by the substance when it burns gives the heat of combustion.

Explanation:

5 0

2 years ago

Consider the reaction 2N2(g) O2(g)2N2O(g) Using the standard thermodynamic data in the tables linked above, calculate Grxn for t

ratelena [41]

Answer:

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

ΔG ≅ 199.91 kJ

Explanation:

Consider the reaction:

$2N_{2(g)} + O_{2(g)} \to 2N_2O_{(g)}$

temperature = 298.15K

pressure = 22.20 mmHg

From, The standard Thermodynamic Tables; the following data were obtained

$\Delta G_f^0 \ \ \ N_2O_{(g)} = 103 .8 \ kJ/mol$

$\Delta G_f^0 \ \ \ N_2{(g)} =0 \ kJ/mol$

$\Delta G_f^0 \ \ \ O_2{(g)} =0 \ kJ/mol$

$\Delta G^0 _{rxn} = 2 \times \Delta G_f^0 \ N_2O_{(g)} - ( 2 \times \Delta G_f^0 \ N_2{(g)} + \Delta G_f^0 \ O_{2(g)})$

$\Delta G^0 _{rxn} = 2 \times 103.8 \ kJ/mol - ( 2 \times 0 + 0)$

$\Delta G^0 _{rxn} = 207.6\ kJ/mol$

The equilibrium constant determined from the partial pressure denoted as $K_p$ can be expressed as :

$K_p = \dfrac{(22.20)^2}{(22.20)^2 \times (22.20)}$

$K_p = \dfrac{1}{ (22.20)}$

$K_p$ = 0.045

$\Delta G = \Delta G^0 _{rxn} + RT \ lnK$

where;

R = gas constant = 8.314 × 10⁻³ kJ

$\Delta G =207.6 + 8.314 \times 10 ^{-3} \times 298.15 \ ln(0.045)$

$\Delta G =207.6 + 2.4788191 \times \ ln(0.045)$

$\Delta G =207.6+ (-7.687048037)$

$\Delta G =$ 199.912952 kJ

ΔG ≅ 199.91 kJ

7 0

4 years ago

Calculate the number of formula units in 2.50 mol NaNO

marta [7]

The number of formula units in 2.50 mol of the compound is 15.1 * 10^23.

The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.

6.02 * 10^23 formula units of the compound are contained in 1 mole

x formula units are contained in 2.5 moles of the compound

x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole

x = 15.1 * 10^23 formula units of the compound.

Learn more; brainly.com/question/9743981

3 0

3 years ago

How many grams are in 1.2 x 1024 atoms of sodium?

jarptica [38.1K]

Answer:

46 g

Explanation:

First we <u>convert 1.2 x 10²⁴ atoms of sodium into moles</u>, using <em>Avogadro's number</em>:

1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 mol

Then we <u>convert 2.0 moles of sodium into grams</u>, using <em>sodium's molar mass</em>:

2.0 mol Na * 23 g/mol = 46 g

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

3 0

3 years ago