Answer:
5.11 kg
Explanation:
Hooke's law states that stress is directly proportional to strain. It can be represented by the equation:
F = -kx
Where x is the displacement of the spring’s end from its equilibrium position, F is the force applied to the spring, k is a constant known as spring constant.
At first a force (F) of 62 N i used to stretch a spring by 12 cm (x).
Substituting into Hooke's equation:
F = kx
k = F/x = 62 / 12 = 5.17 N/cm
The spring is then held vertically and an object. The object is acted by upon by acceleration due to gravity since it is vertically upward. Therefore the force created by the object F = mg where g = acceleration due to gravity = 9.8 m/s². It causes a stretch (x) of 9.7 cm
Therefore:
mg = 5.17 N/cm × 9.7 cm
9.81m = 50.117
m = 50.117 / 9.81 = 5.11 kg
Given Information:
Mass = m = 500 kg
Acceleration = a = 10 cm/s²
Required Information:
Magnitude of rightward net force = F = ?
Answer:
Magnitude of rightward net force = 50 N
Explanation:
From the Newton's second law of motion
F = ma
Where m is the mass and a is the acceleration
To get force in Newtons first convert 10 cm/s² into m/s²
10/100 = 0.1 m/s²
F = 500*0.1
F = 50 N
Therefore, the magnitude of rightward net force acting on it is 50 Newtons.
Hi! ;D
the slope of the line tells us the rate of change of y relative to x. If the slope is 2, then y is changing twice as fast as x; if the slope is 1/2, then y is changing half as fast as x, and so on. ... In other words, if the line is near vertical then y is changing very fast relative to x.