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3 years ago

The position of an ant and a spider in a room are A(2,3,5) and B(6,0,8) determine the distance

Physics

1 answer:

marta [7]3 years ago

4 0

Answer:

$|d| = \sqrt{ {(x_{2} -x_{1})}^{2} + {(y_{2} -y_{1})}^{2} + {(z_{2} -z_{1})}^{2}} \\ = \sqrt{ {(6 - 2)}^{2} + {(3 - 0)}^{2} +{(5 - 8)}^{2} } \\ = \sqrt{16 + 9 + 9} \\ = \sqrt{34}$

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Multiply the following three numbers and report your answer to the correct number of significant figures: 0.020cm x 50cm x 11.1c

Neko [114]

Answer:11.1

Explanation:

Three significant figures

5 0

3 years ago

The uncertainty in the position of an electron along an x axis is given as 68 pm. What is the least uncertainty in any simultane

umka21 [38]

Answer:

$\Delta p_x=7.75\times 10^{-25}\ kg-m/s$

Explanation:

Given that,

The uncertainty in the position of an electron along the x-axis is, $\Delta x=68\ pm=68\times 10^{-12}\ m$

We need to find the east uncertainty in any simultaneous measurement of the momentum component of this electron.

We know that the Heisenberg's uncertainty principle gives the relation between the uncertainty in position and the momentum of electron as :

$\Delta p_x{\cdot}\Delta x\ge \dfrac{h}{4\pi }$

Putting all the values, we get :

$\Delta p_x{\cdot}\ge \dfrac{h}{4\pi \Delta x}\\\\\Delta p_x \ge \dfrac{6.63\times 10^{-34}}{4\pi \times 68\times 10^{-12}}\\\\\Delta p_x\ge 7.75\times 10^{-25}\ kg-m/s$

So, the momentum component of this electrons is greater than $7.75\times 10^{-25}\ kg-m/s$ .

6 0

4 years ago

g A circular loop of wire with radius 3 m is flat on the xy plane in a magnetic field which is pointed in the z-direction and ha

Phantasy [73]

Answer:

emf=-0.035V

Explanation:

this problem can be solved with the Lenz's law:

$emf=-\frac{\Delta \Phi_{B}}{\Delta t}$

where PhiB is the magnetic flux. In this case we have

$\Delta \Phi_{B}=B(A_1-A_2)$

due to the magnetic field is constant. A is the area of the circular loop. Hence

$\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2$

Finally

$emf=-\frac{0.106Tm^2}{3s}=-0.035V$

HOPE THIS HELPS!!

7 0

3 years ago

A Scooter with a mass of 50 kilograms travels with a speed of 10 meters per second. A 2 Nt force bring it to a halt. How long ti

Serga [27]

Answer:

250s

Explanation:

Given parameters:

Mass = 50kg

Speed = 10m/s

Force = 2N

Unknown:

Time the force was acting = ?

Solution:

To solve this problem, we use the equation of motion from the second law of Newton:

Ft = mV

F is the force

t is the time taken

m is the mass

V is the velocity

2 x t = 50 x 10

t = 250s

3 0

3 years ago

A force of 20 newtons is exerted on a chair from its right and a force of 12 newtons is applied from its left. What is the net f

jeka94

The net force is the sum of the forces acting on an object ( chair ).
F net = F 1 + F 2
F 1 = 20 N, F 2 = - 12 N
F net = 20 N + ( - 12 N ) = 8 N
The chair will tend to move to the left.

4 0

3 years ago