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Monica [59]
3 years ago
8

A tennis player swings her 1000 g racket with a speed of 12 m/s. she hits a 60 g tennis ball that was approaching her at a speed

of 16 m/s. The ball rebounds at 42 m/s.
(a) How fast is her racket moving immediatley after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.

__________ m/s

(b) If the tennis ball and racket are in contatc for 10 ms, what is the average force that the racket exerts on the ball?

________ N

How does this compare to the gravitational force on the ball?

F avg / W ball=________
Physics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0

Answer:

should be the answer B

Explanation:

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How have earthquake data been used to explore the size of convection currents in the mantle?
nadezda [96]
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During takeoff, an airplane climbs with a speed of 130 m/s at an angle of 47 degrees above the horizontal. The speed and directi
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3 years ago
Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said
ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

'f'

Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

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When a body performs a uniform circular motion, the direction of the velocity vector changes at every moment. This variation is experienced by the linear vector, due to a force called centripetal, directed towards the center of the circle that gives rise to centripetal acceleration, the mathematical expression is given as,

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The linear velocity was 2010m/s in a radius of 0.159m, then the centripetal acceleration is

a = \frac{2010^2}{0.159}

a = 2.54*10^7m/s^2

Therefore the centripetal acceleration of the end of the rod is 2.54*10^7m/s^2

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