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Monica [59]
4 years ago
8

A tennis player swings her 1000 g racket with a speed of 12 m/s. she hits a 60 g tennis ball that was approaching her at a speed

of 16 m/s. The ball rebounds at 42 m/s.
(a) How fast is her racket moving immediatley after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.

__________ m/s

(b) If the tennis ball and racket are in contatc for 10 ms, what is the average force that the racket exerts on the ball?

________ N

How does this compare to the gravitational force on the ball?

F avg / W ball=________
Physics
1 answer:
tensa zangetsu [6.8K]4 years ago
6 0

Answer:

should be the answer B

Explanation:

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A 100 Kg man is diving off a 50 meter cliff. What is his kinetic energy when he is 20 meters from the water?
iren2701 [21]

Answer:

K.E=29.403125J

Explanation:

From the question we are told that

Mass M=100

Height 50-20=30m

Generally the equation for velocity before impact is is is mathematically given by

v=\sqrt{2gh}

v=\sqrt{2*9.8*30}

v=24.25

Generally the equation for Kinetic Energy is is mathematically given by

K.E=\frac{1}{2}mv^2

K.E=\frac{1}{2}*100*(24.25)^2\\

K.E=29403.125J

K.E=29.403125J

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3 years ago
Compare and contrast microscopic and macroscopic energy transfer Give least three comparisons for each
Eduardwww [97]

Answer:

Differences

microscopic refers to substances visible to the naked eye

macroscopic are substances invisible to naked eye

Similarities

both refer to different scales that are useful to determining the size to different compounds.

Explanation:

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3 years ago
Why is it better to use the metric system, rather than the English system, in scientific measurement?
fiasKO [112]

A. The English system uses one unit for each category of measurement.

4 0
3 years ago
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A 4kg bird is flying with a velocity of 4 m/s. What is its kinetic energy?
Yanka [14]
Kinetic energy = 32 J
8 0
3 years ago
Light of wavelength 600 nm passes though two slits separated by 0.22mm and is observed on a screen 1.1m behind the slits. The lo
Ne4ueva [31]

Answer:

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

Explanation:

We have to take into account the expression for the position of the fringes

dsen\theta=m\lambda\\y=\frac{m\lambda D}{d}

where m is the number of the maximum, d is the separation of the slits, D is the distance to the screen.

(a) By replacing we obtain

y(m=1)=\frac{(1)(600*10^{-9}m)(1.1m)}{0.22m}=3*10^{-6}m\\\\y(m=1)=\frac{(-1)(600*10^{-9}m)(1.1m)}{0.22m}=-3*10^{-6}m

(b)  more information is required to solve this point. Please complete the information.

HOPE THIS HELPS!

4 0
3 years ago
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