The answer is b/ cope a small section word-for-word
The principle of moments states that for a system at equilibrium the clockwise moments is equal to the anticlockwise moments.
Moments is given by force × perpendicular distance
Moments one one side of the seesaw will be 340Nm and on the other will be 500Nm, for balanced or equilibrium to be achieved the two moments should be equal.
Difference is 160 Nm, thus with a child 10 kg to balance the system, then,
Distance will be 16 nm/ 100N = 1.6 m
Threfore, a child of 10 kg should sit at a distance of 1.6m from the pivot on the side with 17 kg child for the system to balance.
(a) the weight of the fish is:
and this is the force that stretches the spring by
. So, we can use Hook's law to find the constant of the spring:
(b) The fish is pulled down by 2.8 cm = 0.028 m more, so now the total stretch of the spring is
But this is also the amplitude of the new oscillation, because this is the maximum extension the spring can get, so A=6.5 cm.
The angular frequency of oscillation is given by:
and so the frequency is given by
Explanation:
107Km/hr=107x5/18=29.72m/s