Answer:
55.7 N
Explanation:
The density of aluminum is 2710 kg/m³. So its volume is:
V = (9 kg) / (2710 kg/m³)
V = 0.00332 m³
The apparent weight is the actual weight minus the buoyant force.
N = mg − B
N = mg − ρVg
N = g (m − ρV)
N = (9.8 m/s²) (9 kg − (1000 kg/m³) (0.0332 m³))
N = 55.7 N
Answer:
2.9 N
Explanation:
When the separation distance, r, is 0.5 m, the electrostatic force is 0.32 N. Electrostatic force is given as:
F = (k * q1 * q2) / r²
Where F = force acting on the balloons
k = Coulombs constant
Therefore:
0.32 = (k * q1 * q2) / 0.5²
=> k * q1 * q2 = 0.32 * 0.5² ------------(1)
When the distance is decreased by 3, that is r = r/3 = 0.5/3
F = (k * q1 * q2) / (0.5/3)² ------------(2)
Putting (1) into (2):
=> F = (0.32 * 0.5²) / (0.5/3)²
F = (0.32 * 0.5² * 3²) / 0.5²
F = 2.9 N
Therefore, the force would be 2.9 N
It has many applications,
Answer:
<em>61.9°</em>
Explanation:
The formula for calculating the workdone is expressed as
Workdone = Fdsin theta
F is the force applied on the crate
d is the distance covered
theta is the angle that the rope makes with the horizontal
Given
F = 40N
d = 7m
Workdone = 247J
Substituting into the formula:
247 = 40(7)sin theta
247 = 280sin theta
sin theta = 247/280
sin theta = 0.88214
theta = arcsin(0.88214)
theta = 61.9°
<em>Hence the angle that the rope makes with the horizontal is 61.9°</em>
Answer:
Explanation:
e. At the right edge of the beam
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