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NeX [460]
3 years ago
11

How does the brightness of light change when a point source of light is brought twice as far away?

Physics
1 answer:
Andru [333]3 years ago
3 0

Answer:

If its twice as far the light will be twice as bright.

Explanation:

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How many ways can motion change
meriva

Answer:

There are four main ways of doing that :-

  • Velocity
  • Acceleration
  • Momentum
  • Kinetic energy

Hope it helps!

7 0
4 years ago
Read 2 more answers
What pressure in units of torr is equal to 1.14 atm of pressure?
likoan [24]
1 atm / 760torr or 760torr / atm -->
1.14atm / 1 × 760torr / atm = 1.14×760torr = 866.4torr
7 0
4 years ago
When the starter motor on a car is engaged, there is a 300 A cunent in the wires between the bauery and the motor. Suppose the w
docker41 [41]

Answer:

diameter of transmission is 3.473 mm

Explanation:

given data

current = 300 A

total wire length = 1.0 m

voltage drop = 0.55 V

solution

as here Resistivity of copper is = 1.68 × 10^{-8} ohm- m

so we get here resistance of wire that is

resistance = \frac{V}{I}    ..............1

R = \frac{0.55}{310}  

R = 1.774 × 10^{-3}  ohm

and now we get diameter of wire that is

R = \frac{\rho l}{A}    .............2

\pi \frac{d^2}{4} = \frac{\rho l}{R}    

d² = \frac{4\rho l}{\pi R}     ...............3

put here value

d² = \frac{4\times 1.68\times 10^{-8} \times 1}{\pi \times 1.774\times 10^{-3}}  

d = \sqrt{12.064\times 10^{-6}}

d = 3.473 × 10^{-3} m

d = 3.473 mm

so diameter of transmission is 3.473 mm

4 0
4 years ago
If it took 125 seconds to complete 5 wave cycles, what is the period of the wave?
finlep [7]

The period of the wave is 25 s

<u>Explanation:</u>

To find the period of the wave, we have the formula

T= seconds/ no of cycle

T= 125/5

T= 25 s

The period of the wave is 25 s

4 0
4 years ago
Use hubble's law to determine the distance to a galaxy which is moving away at a velocity of 3,500 km/s. (assume that h = 70 km/
lorasvet [3.4K]
The solution for this problem:
The distance in mega parsec is equal to recession velocity / H, where h is equal to 50 mega parsec.The explanation for this is:1 parsec = 2.E+05 AU, nearly. 50 mega parsec = 1. E+13 AU, nearly. 1 mega means E+06 (million).
5 0
3 years ago
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