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Snowcat [4.5K]
4 years ago
14

If it took 125 seconds to complete 5 wave cycles, what is the period of the wave?

Physics
1 answer:
finlep [7]4 years ago
4 0

The period of the wave is 25 s

<u>Explanation:</u>

To find the period of the wave, we have the formula

T= seconds/ no of cycle

T= 125/5

T= 25 s

The period of the wave is 25 s

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(TCO 4) A signal consists of only two sinusoids, one of 65 Hz and one of 95 Hz. This signal is sampled at a rate of 245 Hz. Find
storchak [24]

Answer:

65 Hz, 95 Hz, 150 Hz, 180 Hz, 310 Hz, 340 Hz

Explanation:

Given :

Frequencies of the sinusoids,

$f_{m_1}= 65 \ Hz$ ,  and

$f_{m_2}= 95 \ Hz$

Sampling rate f_s = \ 245 \ Hz

The positive frequencies at the output of the sampling system are :

$f_{o_1}=\pm f_{m_1} \pm nf_s, f_{o_2}=\pm f_{m_2} \pm nf_s $

When n = 0,

$f_{o_1}= f_{m_1} = 65 \ Hz,\ \  f_{o_2}= f_{m_2} = 95 \ Hz $

when n  = 1,

$f_{o_1}=\pm f_{m_1} \pm f_s, \ \ f_{o_2}=\pm f_{m_2} \pm  f_s $

$f_{o_1}= \pm 65 \pm 245,\ \  f_{o_2}=\pm 95 \pm 245$

$f_{o_1}= 180 \ Hz, 310 \ Hz,\ \  f_{o_2}= 150 \ Hz,340 \ Hz$

When n = 2,

$f_{o_1}= \pm 65 \pm 2(245),\ \  f_{o_2}=\pm 95 \pm 2(245)$

$f_{o_1}= 555 \ Hz, 425 \ Hz,\ \  f_{o_2}= 395 \ Hz,585 \ Hz$

Therefore, the first six positive frequencies present in the replicated spectrum are :

65 Hz, 95 Hz, 150 Hz, 180 Hz, 310 Hz, 340 Hz

8 0
3 years ago
In one cycle, a freezer uses 800 J of electrical energy in order to remove 1735 J of heat from its freezer compartment at 10.0°F
Lubov Fominskaja [6]

Answer:

Explanation:

A)

W = work done by the freezer = 800 J

Q = heat removed from the freezer = 1735 J

Q' = Heat expelled into the room

Coefficient of performance is given as

\beta = \frac{Q}{W}

inserting the values

\beta = \frac{1735}{800}

\beta = 2.2

B)

Heat expelled is given as

Q' = W + Q

Q' = 800 + 1735

Q' = 2535 J

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Svetlanka [38]

The formula written in the 3rd line above the picture is WRONG. Don't use it.  Use the formula the way it's printed in the picture.

V = d / t

That means  Speed = (distance) / (time)

The question tells us that v = 330 m/s

So you write 330 m/s in the equation in place of 'v', like this:

330 m/s = (distance) / (time)

The question also tells us that the time is 0.4 second

So you write 0.4 sec in place of 'time', like this:

330 m/s = (distance) / (0.4 second)

Finally, you take this, and multiply each side of the equation by (0.4 sec).  Then it'll say

distance = (330 m/s) x (0.4 second)

As soon as you do that one single multiplication there with your pencil or your calculator, you'll have the distance.

This is either the 2nd or 3rd time you've posted this same exact question since last weekend.  It can be solved THIS time exactly like the answers that were posted those other times.

The DOT in the picture is marked for the wrong choice.  Use the formula that's printed in the picture, not copied above it.

6 0
3 years ago
Write one advantage of MKS system over CGS system.​
Temka [501]
More convenient
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7 0
3 years ago
Calculate the pressure exerted on the ground when a woman wears high heals. Her mass is 65 kg. and the area of each heal is 1 cm
erma4kov [3.2K]

Answer:

318.5 x 10^4 Pa

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weight of woman = m g = 65 x 9.8 = 637 N

Area of both the heels = 1 x 2 = 2 cm^2 = 2 x 10^-4 m^2

Pressure is defined as the thrust acting per unit area.

P = F / A

Where, F is the weight of the woman and A be the area of heels

P = 637 / (2 x 10^-4) = 318.5 x 10^4 Pa

8 0
3 years ago
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