A 2m long rope is stretched between two supports with a tension that makes the speed of transverse waves 50m/s. What is the wave
1 answer:
Answer: 4m
Explanation:
In this situation, while the rope vibrates, a periodic wave travels through it, which is a standing wave.
In this sense, a standing wave has several harmonics and a f<u>undamental tone</u> (also called fundamental frequency), which is the lowest frequency of this periodic wave and is given by:
(1)
Where:
is the fundamental frequency
is the speed of the wave
is the longitude of the rope
On the other hand, there is a relation between and the wavelength
of the fundamental tone:
(2)
Finding from (2):
This is the wavelength of the fundamental tone
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Answer:
The work done on the system can be accounted for by;
Both and
Explanation:
The speed of the crate = Constant
Therefore, the acceleration of the crate = 0 m/s²
The net force applied to the crate, = 0
Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate
However, we have;
The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate
The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system
The weight of the crate × The height the crate is raised = Gravitational Potential Energy =
The heat generated as internal energy to the system =
Therefore;
The work done on the system = +
.
The gravitational force exerted on the moon by the planet when the moon is at maximum distance 
is
where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.
Similary, the gravitational force at minimum distance is
And this is the maximum force, since the distance between planet and moon is minimum.
The problem says that
exceeds 
by 11%. We can rewrite this as
Substituing the formulas of Fmin and Fmax, this equation translates into
and so, the ratio between the maximum and the minimum distance is
where G is the gravitational constant, M and m are the planet and moon masses, respectively. This is the minimum force, because the planet and the moon are at maximum distance.
Similary, the gravitational force at minimum distance is
And this is the maximum force, since the distance between planet and moon is minimum.
The problem says that
Substituing the formulas of Fmin and Fmax, this equation translates into
and so, the ratio between the maximum and the minimum distance is
Answer:
In a nutshell, units of A and B are and
, respectively.
Explanation:
From Dimensional Analysis we understand that and
have length units (
) and
have time units (
). Then, we get that:
(Eq. 1)
(Eq. 2)
Now we finally clear each constant:
In a nutshell, units of A and B are and
, respectively.