Can someone help me out with the last three, will mark as brainliest if correct!
1 answer:
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The mean of data is 164.70, median and mode of data are 164
Given that Dataset: 147; 159; 164; 182; 172; 171; 162; 163; 157; 145; 164; 188; 172; 163; 162; 164 and 166. and asked to arrange data in stem and leaf diagram and asked to determine mean, mode and median form the stem and leaf diagram
STEM LEAF
14 5 7
15 7 9
16 2 2 3 3 4 4 4 6
17 1 2 2
18 2 8
Mean= 164.70
Median⇒since there are 17 terms
Median= the term
Median=9th term=164
Mode⇒ most frequent number
Mode⇒164
Therefore, 164 is mode and median ,164.70 is mean
Hence,The mean of data is 164.70, median and mode of data are 164
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Answer:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*e-4-(6*e*(45+2*e))=0
Step by step solution :
STEP
1
:
Equation at the end of step 1
(3e - 4) - 6e • (2e + 45) = 0
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-12e2 - 267e - 4 = -1 • (12e2 + 267e + 4)
Trying to factor by splitting the middle term
3.2 Factoring 12e2 + 267e + 4
The first term is, 12e2 its coefficient is 12 .
The middle term is, +267e its coefficient is 267 .
The last term, "the constant", is +4
Step-1 : Multiply the coefficient of the first term by the constant 12 • 4 = 48
Step-2 : Find two factors of 48 whose sum equals the coefficient of the middle term, which is 267 .
Step-by-step explanation:
