Speed = Distance / time
Distance = Speed x time
In t hours, first plane travels = 600 t miles
In t hours, the second plane travels =150 t miles
After t hours the distance between the two planes is:
(600t+150t)= 750t ( since both travel in opposite directions)
When the distance is 900 miles:
750t= 900
Solve for t:
t= 900/750
t= 1.2 hours
After 1.2 hours.
1.2 x 60 = 72 minutes = 60 +12 = 1 hour and 12 minutes
Since both leave at 10 pm:
10am + 1 hour and 12 minutes : 11:12 am
They will be 900 miles apart at 11:12 am
Each one traveled:
Plane 1:
Distance: Speed x time = 600 mph x 1.2 = 720 miles
Plane 2:
Distance = Speed x time = 150 mph x 1.2 = 180 miles
Answer is
-2
Hope this helped! :)
Answer: She invested $12000 in fund B.
Step-by-step explanation:
Let x represent the amount which she invested in fund A.
Let y represent the amount which she invested in fund B.
The amount she invested in Fund A was twice as much as the amount she invested in fund B. This means that
x = 2y
Fund A returned a 7% profit. It means that the profit returned from fund A is
7/100 × x = 0.07x
Fund B returned a 5% profit. It means that the profit returned from fund B is
5/100 × y = 0.05y
if total profit from the two funds together was $2280, it means that
0.07x + 0.05y = 2280- - - - - - - - - - -1
Substituting x = 2y into equation 1, it becomes
0.07 × 2y + 0.05y = 2280
0.14y + 0.05y = 2280
0.19y = 2280
y = 2280/0.19
y = 12000
x = 2y = 2 × 12000
x = 24000
6.40312 is the <span>hypotenuse
</span>
Answer:
4/5
Step-by-step explanation:
1+3=4
