What is the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15

1 answer:

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Answer:

x + 3y = 9

Step-by-step explanation:

The parallel line will have the same x- and y-coefficients. The new constant can be found by using the (x, y) values of the given point.

x + 3y = (6 +3(1)) = 9

The equation of the parallel line is ...

x + 3y = 9

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