What is the equation of the line that passes through the point (6,1) and is parallel to the line x+3y=15
1 answer:
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Answer:
x + 3y = 9
Step-by-step explanation:
The parallel line will have the same x- and y-coefficients. The new constant can be found by using the (x, y) values of the given point.
x + 3y = (6 +3(1)) = 9
The equation of the parallel line is ...
x + 3y = 9
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