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avanturin [10]
3 years ago
15

I´m on an escape room. I need the answer.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

K>7

Step-by-step explanation:

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PLEASE HELP Graph 4x + y = 6x - 1 Show your work AND explain the method used to determine the graph
Anna007 [38]

Answer:

y=2x-1

Step-by-step explanation:

y= 6x-1-4x

y=2x-1

3 0
4 years ago
Which statements are true about the solution of 15 greater-than-or-equal-to 22 + x? Select three options. x greater-than-or-equa
Sidana [21]

Answer:

x \leq  -7

The graph has a closed circle.

–7 is part of the solution.

Step-by-step explanation:

Given

15 \geq 22 + x

Required

Select 3 options from the given list of options

15 \geq 22 + x

Subtract 22 from both sides

15 - 22 \geq 22 - 22+ x

-7 \geq x

Swap positions of the expression; Note that the inequality sign will change

x \leq  -7

This means  <em>x less-than-or-equal-to negative 7</em>

<em></em>

There are two options left to select;

The inequality sign in x \leq  -7 implies that the graph has a close circle.

Inequality signs such as \leq and  \geq signifies a close circle

There is only one option left to select;

Lastly;

Split the expression x \leq  -7 into two

We have:

x < -7 or x = -7

Because x = 7,

Then, -7 is also a part of the solution

3 0
4 years ago
HELPPPP PLEASE IN NEED HELP FAST I NEED ALL 5 DONE
Radda [10]

1. 11h

2. 10w

3. 6w

4.6 (h+3)

5. 74

hope it's helpful.

6 0
3 years ago
Determine whether the polynomial below can be factored into perfect squares. If so, factor the polynomial. Otherwise, select tha
Natasha2012 [34]

Answer:

C. (4x-8)^2

Step-by-step explanation:

We need to determine whether the given polynomial 16x^2-64x+64 can be factored into perfect squares. If so, factor the polynomial. Otherwise, select that it cannot be factored into a perfect square.

16x^2-64x+64

=16x^2-32x-32x+64

=16x(x-2)-32(x-2)

=(16x-32)(x-2)

=16(x-2)(x-2)

=16(x-2)^2

=4^2(x-2)^2

=(4(x-2))^2

=(4x-8)^2

Hence final answe is choic C. (4x-8)^2

6 0
4 years ago
.....................................................
Xelga [282]

Step-by-step explanation:

hii I wanna ask something

3 0
3 years ago
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