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ValentinkaMS [17]
3 years ago
15

Part A

Chemistry
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

double layered vacuum seal as the thermal insulators to make a liuqid hot when it cold and keep it cold when its hot.

Explanation:

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In which Earth system does the rock cycle take place?
e-lub [12.9K]

Answer:

geosphere

Explanation:

geo means rocks this is the area

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6 0
3 years ago
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What kind of change occurs when I’ve becomes liquid water
gregori [183]

Answer:

Its a physical

theres no chemical properties involved.

Explanation:

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6 0
3 years ago
11. Propane (C3Hg) is a fuel commonly used in gas grills.
Mrac [35]

Answer:

81.71%

Explanation:

One mole of propane contains 3 moles of carbon atoms and 8 moles of hydrogen atoms, as seen from the molecular formula of C_3H_8. In order to calculate the percent of carbon in propane by mass, we need to remember that %w/w (or percent mass) formula states that:

\omega=\frac{m_{component}}{m_{total}}\cdot100\%

That is, we need to divide the mass of the component of interest by the total mass of the compound and multiply by 100 to obtain the percentage.

For simplicity, let's take 1 mole of propane and find the mass of 1 mole (hence, we'll be finding the molar mass of propane). To do that, we add the 3 molar masses of carbon and 8 molar masses of hydrogen to obtain a total of:

M_{C_3H_8}=3M_C+8M_H=3\cdot12.011 \frac{g}{mol}+8\cdot1.00784\frac{g}{mol}=44.096 \frac{g}{mol}

Now that we have the molar mass of propane, we also need to find the total mass of carbon in 1 mole of propane. We know that we have a total of 3 moles of carbon which corresponds to:

M_C=3\cdot12.011 \frac{g}{mol}=36.033 \frac{g}{mol}

Dividing the mass of carbon present by the total mass of the compound will yield the mass percentage as defined by the formula we introduced:

\omega_C=\frac{36.033\frac{g}{mol}}{44.096 \frac{g}{mol}}\cdot 100\%=81.71\%

5 0
3 years ago
Describe a process in which energy changes form at least two times explain how the law of conservation of energy applies to the
Dmitry_Shevchenko [17]
A pendulum.  Hold it high and it has potential energy but no kinetic energy because it is still.  As it moves down when you drop it, it changes to kinetic energy and moves faster and faster until it's at the bottom where it has no potential energy.  However, it still has momentum, so now it is changed to potential energy as it moves up the other side
5 0
4 years ago
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
4 years ago
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