Answer:
yes
Explanation:
it wont dissolve because when water is cold its molecules dont separate
Answer:
Calories of candy = 5.1 kcal /g
Explanation:
Given data:
Mass of candy = 4.70 g
Change in temperature = 2.46 °C
Specific heat capacity of calorimeter = 40.50 Kj/°C
Calories present per gram = ?
Solution:
Formula
Cal of candy = specific heat capacity × change in temperature / mass
C = c . ΔT/m
C = 40.50 Kj/°C × 2.46 °C / 4.70 g
C = 99.63 kj /4.70 g
C = 21.2 kj/ g
C = 21.2 kj/ g × 0.239 kcal/kj
C = 5.1 kcal /g
Answer:
A) Concentration
Explanation:
When you add a chemical to itself it becomes more concentrated making it more powerful and faster
Answer:
d.) 1.0 M HNO2, 1.0 M NaNO2
Explanation:
A buffer is a mixture that is capable of tolerating addition of a strong acid or base without altering the pH substantially.
A buffer is the mixture of a <em>WEAK ACID AND ITS CONJUGATE BASE </em>or a <em>WEAK BASE AND ITS CONJUGATE ACID</em>
<em></em>
In the problems:
a) HCl is a strong acid and NaCl a salt. NO buffer
b) NH3 is a weak base and NaCL a salt. NO buffer
c) HF is a weak acid and NaCl a salt. NO buffer.
<h3>d) HNO2 is a weak acid and NaNO2 its conjugate base. A BUFFER</h3>
Answer:
The statement is FALSE.
Explanation:
It is known as the ion effect common to the displacement of an ionic equilibrium when the concentration of one of the ions that are involved in said equilibrium changes, due to the presence in the dissolution of a salt that is dissolved in it.
Given the reaction of the dissociation reaction of a weak electrolyte:
AB (s) ⇔ A⁺(aq) + B⁻ (aq)
The equilibrium constant of the reaction is:
![K_{ps}=\frac{[A^+][B^-]}{[AB]}](https://tex.z-dn.net/?f=K_%7Bps%7D%3D%5Cfrac%7B%5BA%5E%2B%5D%5BB%5E-%5D%7D%7B%5BAB%5D%7D)
Given the reaction of the dissociation reaction of a stong electrolyte:
CB (s) ⇒ C⁺(aq) + B⁻ (aq)
If the electrolyte CB is added to the medium in which electrolyte AB is found, the medium will have a common ion B⁻:
AB (s) ⇔ A⁺(aq) + B⁻ (aq)
CB (s) ⇒ C⁺(aq) + B⁻ (aq)
By the Le Chatelier's principle, having more concentration of products, the balance will shift to the right.
Hence, the extent of ionization of a weak electrolyte is decreased by adding to the solution a strong electrolyte that has an ion in common with the weak electrolyte.