Answer:
A) 31.22
Explanation:
The reaction of sulfuric acid with NaOH is:
H₂SO₄ + 2 NaOH → Na₂SO₄ + 2H₂O
To solve this problem we need to determine the moles of acid that will react, and, using the chemical equation we can determine the moles of NaOH and the volume that a 0.2389M NaOH solution would require to neutralize it.
<em>Moles H₂SO₄ (Molar mass: 98.08g/mol):</em>
0.9368g * 39.04% = 0.3657g H₂SO₄ * (1mol / 98.08g) =
3.7289x10⁻³moles H₂SO₄
And moles of NaOH that you require to neutralize the acid are:
3.7289x10⁻³moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) =
7.4578x10⁻³ moles NaOH
Using a 0.2389M NaOH solution:
7.4578x10⁻³ moles NaOH * (1L / 0.2389mol) = 0.03122L = 31.22mL
Right answer is:
<h3>A) 31.22
</h3>
It is less dense than the liquid below it
Answer:
Explanation:
Relation of with is given by the formula:
where,
= equilibrium constant in terms of partial pressure
= equilibrium constant in terms of concentration
R = Gas constant
T = temperature
= change in number of moles of gas particles =
when = 0
a)
= change in number of moles of gas particles =
b)
= change in number of moles of gas particles =
c)
= change in number of moles of gas particles =
d)
= change in number of moles of gas particles =
Thus for reaction , , as = 0
I think the correct answer from the choices listed above is the first option. The statement that is true would be that compounds that can form more hydrogen bonds are more soluble in water. Hope this answers the question. Have a nice day.