Answer:
it has 9 sulfur atoms
Explanation:
you have to multiply the 3 outside the bracket by the one in side to get your answer
The mass of chlorine required to react with 10.0 g of sodium metal to produce sodium chloride is 15.26 g.
The balanced chemical reaction is :
<em> 2Na + Cl₂ → 2NaCl</em>
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Given data :
Mass of sodium = 10.0 g
Number of moles of Na -
Number of moles = <u> Given mass </u>
Molar mass
Number of moles = <u> 10.0 g</u> = 0.43 mol
23 g
Comparing moles of Na and Cl₂ from the balanced chemical equation,
Na : Cl₂
2 : 1
0.43 : <u> 1 </u> x 0.43 = 0.215 mol
2
Mass of chlorine gas :
(molar mass of chlorine = 71 g)
Mass of chlorine = number of moles x molar mass
Mass = 0.215 mol x 71 g/mol
= 15.26 g
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Answer and Explanation:
The reaction is in the gas phase, so the equilibrium constant is expressed in terms of the partial pressures (P) of the products and reactants, as follows:

We have the following data:
P(SO₃) = 2.6 atm
P(O₂) = 0.43 atm
We need Kp for this reaction. We can assume that in Appendix 4 we found that Kp = 7 x 10²⁴.
Then, we introduce the data in the equilibrium constant expression to calculate the partial pressure f SO₂ (PSO₂), as follows:

Therefore, the partial pressure of SO₂ is 1.5 x 10⁻¹² atm (for the given Kp).