a) Carbon and oxygen are chemically bonded in carbon dioxide.
The elements lose their individual identities in CO₂, and they always combine o the proportion C:O = 1:2.
You cannot separate the elements from each other by physical means.
Answer: B
Explanation: The clouds act almost like a lid. Think of it like when you put tin foil over food before it goes in the oven. so that even after it is removed from the heat the tin foil traps it causing it to stay warm.
Answer:
![\boxed {\boxed {\sf 53, 346 \ Joules}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%2053%2C%20346%20%5C%20Joules%7D%7D)
Explanation:
We are given the specific heat and change in temperature, so we should use this heat formula:
![q=m C \Delta T](https://tex.z-dn.net/?f=q%3Dm%20C%20%5CDelta%20T)
where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.
We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.
Let's find the change in temperature.
Subtract the initial temperature from the final temperature.
- ΔT= final temp - initial temp
- final= 95.0 °C and initial= 10.0 °C
- ΔT= 95.0 °C - 10.0 °C= 85.0 °C
Now we know all the values:
![m= 150 \ g \\C= 4.184 J/ g \ \textdegree C \\\Delta T= 85.0 \textdegree C](https://tex.z-dn.net/?f=m%3D%20150%20%5C%20g%20%5C%5CC%3D%204.184%20J%2F%20g%20%5C%20%20%5Ctextdegree%20C%20%5C%5C%5CDelta%20T%3D%2085.0%20%5Ctextdegree%20C)
Substitute them into the formula.
![q=(150 \ g) (4.184 \ J/g \ \textdegree C)(85.0 \textdegree C )](https://tex.z-dn.net/?f=q%3D%28150%20%5C%20g%29%20%284.184%20%5C%20J%2Fg%20%5C%20%5Ctextdegree%20C%29%2885.0%20%5Ctextdegree%20C%20%29)
Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.
![q=(627.6 \ J/ \textdegree C) ( 85.0 \textdegree C)](https://tex.z-dn.net/?f=q%3D%28627.6%20%5C%20J%2F%20%5Ctextdegree%20C%29%20%28%2085.0%20%5Ctextdegree%20C%29)
![q=53346 \ J](https://tex.z-dn.net/?f=q%3D53346%20%5C%20J)
<u>53,346 Joules</u> of heat are required.
12.5 mols of glucose are in 5 liters of the 2.5 M solution.
Answer:
electrophile is pe do file
Explanation:
elecricity = needing a professor= creepy profesor= pe edo