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egoroff_w [7]
3 years ago
10

How can a sudden surge of fresh water from an estuary pollute the ocean?

Chemistry
1 answer:
andrew11 [14]3 years ago
3 0
It might have trash, mud, pee, or oil in it.

Hope This Helps If So Can U Mark Me Brainliest
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An atom or ion has 16 protons, 15 neutrons, and 17 electrons. Is it positive, negative, or
azamat
Its negative I think, if I remember correctly it is phosphorus-32....
7 0
2 years ago
Ethanol (c2h5oh) melts at -114°c. the enthalpy of fusion is 5.02 kj/mol. the specific heats of solid and liquid ethanol are 0.9
maria [59]
You'll want to add three amounts of heat. 

(1) Specific heat of lowering the temperature from -135°C to the melting point -114°C
(2) Latent heat of fusion/melting
(3) Specific heat of elevating the temperature from -114°C to -50°C

(1) E = mCΔT = (25 g)(0.97 J/g·°C)(1 kJ/1000 J)(-114 - -135) = 0.509 kJ
(2) E = mΔH = (25 g)(5.02 kJ/mol)(1 mol/46.07 g ethanol) = 2.724 kJ
(3) E = mCΔT = (25 g)(2.3 J/g·°C)(1 kJ/1000 J)(-50 - -114) = 3.68 kJ

<em>Summing up all energies, the answer is 6.913 kJ.</em>
7 0
3 years ago
Help with 5b. Full explanation please
larisa86 [58]
Not elementary school work
8 0
3 years ago
answer now please Which device can be used to separate nails from sawdust most efficiently? A. strainer B. magnet C. colander D.
e-lub [12.9K]
A magnet because it will remove only metal and not the saw dust

Hope this helps
6 0
3 years ago
Read 2 more answers
How many grams of Co3+ are present in 2.34 grams of cobalt(III) nitrite?
Assoli18 [71]

Answer:

m_{Co^{3+}}=0.563gCo^{3+}

Explanation:

Hello there!

In this case, since these mole-mass relationships are understood in terms of the moles of the atoms forming the considered compound, we first realize that the chemical formula of the cobalt (III) nitrate is Co(NO₃)₃ whereas there is a 1:1 mole ratio of the cobalt (III) ion (molar mass = 58.93 g/mol) to the entire compound. In such a way, we first compute the moles of the salt (molar mass = 58.93 g/mol) and then apply the aforementioned mole ratio to obtain the grams of the required cation:

m_{Co^{3+}}=2.34gCo(NO_3)_3*\frac{1molCo(NO_3)_3}{244.95 gCo(NO_3)_3} *\frac{1molCo^{3+}}{1molCo(NO_3)_3} *\frac{58.93gCo^{3+}}{1molCo^{3+}} \\\\m_{Co^{3+}}=0.563gCo^{3+}

Best regards!

4 0
2 years ago
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