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diamong [38]
4 years ago
9

What is the empirical formula for naphthalene

Chemistry
1 answer:
german4 years ago
5 0

1.Start with the number of grams of each element, given in the problem.

2.Convert the mass of each element to moles using the molar mass from the periodic table.

3.Divide each mole value by the smallest number of moles calculated.

4.Round to the nearest whole number. This is the mole ratio of the elements and is.

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If 980kJ of energy as heat are transferred to 6.2L of water at 291 K what will the final temperature be? The specific heat of wa
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Answer:

Final temperature = T₂ = 328.815 K

Explanation:

Given data:

Given energy = 980 KJ = 980×1000= 980000 J

Volume = 6.2 L

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Formula:

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we will first convert the litter into milliliter

6.2 × 1000 = 6200 mL

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6200 mL = 6200 g

Now we will put the values in formula,

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980000 j = 25916 j/ k .  (T₂ - 291 K)

980000 j /  25916 j/ k =  T₂ - 291 K

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4 years ago
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