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3 years ago

25-LV

Mathematics

1 answer:

Shkiper50 [21]3 years ago

6 0

Answer:

Step-by-step explanation:

you divide the amos number is give you

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A line has a slope of -2 and passes through the point (1,-2). what is an equation of this line ?

Ket [755]

Y=-2x would be the answer.

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2 years ago

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What is the distance from point (– 1, 3) to the line 3x – 4y = 10?

natta225 [31]

Answer:

5 units

Step-by-step explanation:

The distance from a point (m, n ) to the line Ax + By + C = 0 is given by

d = $\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }$

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = $\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }$

= $\frac{|-3-12-10|}{9+16}$

= $\frac{|-25|}{\sqrt{25} }$

= $\frac{25}{5}$

= 5

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2 years ago

Find the distance between the points.<br><br> (4,6),(9,6)

andrezito [222]

Answer:

Step-by-step explanation:

Find the difference between coordinates:

(x²-x1) = (9 - 4) = 5

(y²-y1) = (6 - 6) = 0

Square the results and sum them up:

(5)² + (0)² = 25 + 0 = 25

Now Find the square root

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2 years ago

The length of each side of a square increases by 2.5 inches to form a new square with a perimeter of 70 inches. The length of ea

densk [106]

Check the picture below.

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2 years ago

Describe and correct the error in finding csc θ, given that θ is an acute angle of a right triangle and cos θ =7/11

a_sh-v [17]

Answer:

<h2>cosecθ = 1/sinθ = 11/6√2</h2>

Step-by-step explanation:

Given that cos θ =7/11, cosec θ = 1/sinθ in trigonometry.

Based on SOH, CAH, TOA;

cosθ = adjacent/hypotenuse = 7/11

adjacent = 7 and hyp = 11

Since sinθ = opp/hyp, we need to get the opposite to be able to calculate sinθ.

Using pythagoras theorem to get the opposite;

$hyp^{2} = adj^{2} + opp ^{2} \\opp = \sqrt{hyp^{2} - adj^{2} } \\opp = \sqrt{11^{2} - 7^{2}} \\opp = \sqrt{72} \\opp = 6\sqrt{2}$

sinθ = 6√2/11

cosecθ = 1/sinθ = 1/( 6√2/11)

cosecθ = 1/sinθ = 11/6√2

Note the error; cscθ $\neq$ 1/cosθ but cscθ = 1/sinθ

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2 years ago