A table can be represented with a linear function equation as y = mx + b, where m is the slope and b is the y-intercept.
<h3>How to Represent a Table with Linear Function?</h3>
Assuming we have a table of values as shown in the image attached below, to write an equation of linear function for the table, do the following:
Pick two pairs of values, say, (1, 5) and (2, 25) and find the slope (m):
Slope (m) = change in y / change in x = (25 - 5)/(2 - 1)
Slope (m) = 20
Find the y-intercept (b) by substituting (x, y) = (1, 5) and m = 20 into y = mx + b:
5 = 20(1) + b
5 = 20 + b
5 - 20 = b
-15 = b
b = -15
Write the equation of the linear function by substituting m = 20 and b = -15 into y = mx + b:
y = 20x - 15
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Answer:
Correct answer: (x - 10)² + y² = 441 / 4
Step-by-step explanation:
Given:
(a, b) = (10, 0) the coordinates of the center of the circle
(10, 21/2) circle passing through this point
The standard form of the circle equation is:
(x - a)² + (y - b)² = r² where r is radius of the circle
We will replace the given coordinates of the center of the circle and the point it passes through to get the radius of the circle:
(10 - 10)² + (21/2)² = r² ⇒ r² = (21/2)² = 441 / 4
r² = 441 / 4
(x - 10)² + y² = 441 / 4
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The slope of a line with those points is 1/6m. To find a perpendicular slope find the reciprocal of the slope of the first line. The slope is 6m.
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A+b=(-3n+2)+(5n-7)
=(5-3n)+(2-7)
=2n-5
Came up with the same answer as the first guy