Answer:
The point C is 12.68 km away from the point A on a bearing of S23.23°W.
Step-by-step explanation:
Given that AB is 50 km and BC is 40 km as shown in the figure.
From the figure, the length of x-component of AC = |AB sin 80° - BC cos 20°|
=|50 sin 80° - 40 cos 20°|=11.65 km
The length of y-component of AC = |AB cos 80° - BC sin 20°|
=|50 cos 80° - 40 sin 20°|= 5 km
tan
= 5/11.65
=23.23°
AC= 
km
Hence, the point C is 12.68 km away from the point A on a bearing of S23.23°W.
Answer:
w = 0, 5
Step-by-step explanation:
<h3>
I'll teach you how to solve f(x)=0x63 - 52x – 96</h3>
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f(x)=0x^3 - 52x – 96
Apply rule:
0 * a= 0
0-52x-96
Group like terms:
-52x+0-96
Add/subtract the numbers:
0-96= -96
-52x-96
Your Answer Is -52x-96
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Answer: 6
Step-by-step explanation:
because i said so
Answer:
The answer is 82 unit total
Step-by-step explanation:
You can take the entire shape and break it down to normal shapes such as squares and triangles. Then you can use the formula of these shapes to find the area. Last you add all the unit together and that's the answer
