Question

A balloon filled with helium has a volume of 30.0 L at a pressure of 100 kPa and a temperature of 15.0°C. What will the volume of the balloon be if the temperature is decreased to -80.0°C and the pressure remains constant?

Answer 1

Answer:

$V_2=20.1L$

Explanation:

Hello there!

In this case, since this is a problem in which the pressure of the gas remains constant, we can use the Charles' law as a directly proportional relationship between temperature (in Kelvins) and volume given by:

$\frac{V_2}{T_2} =\frac{V_1}{T_1}$

Thus, solving for the final volume as the temperature is decreased to -80.00 °C, we obtain:

$V_2=\frac{V_1T_2}{T_1}$

$V_2=\frac{30.0L*(-80+273)K}{(15+273)K} \\\\V_2=20.1L$

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