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AfilCa [17]
3 years ago
14

How many mL of 0.200M KI would contain 0.0500 moles of KI? Please explain and show work.

Chemistry
2 answers:
Naddika [18.5K]3 years ago
6 0
  • Molarity=0.2M
  • No of moles=0.05mol

We know

\boxed{\Large{\sf Molarity=\dfrac{No\:of\:moles\:of\:solute}{Volume\:of\:solution\:in\;\ell}}}

\\ \Large\sf\longmapsto Volume\:of\:KI=\dfrac{0.05}{0.2}

\\ \Large\sf\longmapsto Volume\:of\:KI=0.25L

\\ \Large\sf\longmapsto Volume\:of\:KI=250mL

valina [46]3 years ago
4 0

Answer:

250ml

Explanation:

call it V

V*0.2=0.05 (moles)

so V=0.05/0.2 = 0.25l = 250ml

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Agata [3.3K]

Answer: \Delta G_{rxn}=130.19J

Explanation:

The balanced chemical reaction is,

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The expression for Gibbs free energy change is,

\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]

\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]

where,

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Now put all the given values in this expression, we get

\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]

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A compound that donates hydrogen ions to a solution is.
jenyasd209 [6]

Your answer is, an acid

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<u>Acid Rain</u>

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