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3 years ago

1. Samantha Hayes worked 38.75 hours at Tech Pro. She is paid $14.625 an hour. What is her

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

3 0

The answer I believe is $566.719. B.

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Consider the following argument: If pigs have wings, then pigs can fly. If pigs are lighter than air, then pigs can fly. Pigs ha

Darina [25.2K]

Answer:

a ) If r ⇒ p

If q ⇒ p

r ∪ q

If r∪p ⇒ ¬ r

∴ s

b) The argument is invalid

Step-by-step explanation:

The argument is invalid because we do not with precision if b), because we do not have enough information about it, and this is because the previous sentences does not mention information about the donkey. We cannot infer something when we do not have enough information.

3 0

3 years ago

-b - 7?

Olegator [25]

Answer:

4 better xplanation inbox

Step-by-step explanation:

8 0

3 years ago

Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"

vampirchik [111]

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h$

Employ a standard trick used in proving the chain rule:

$\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h$

The limit of a product is the product of limits, i.e. we can write

$\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)$

The rightmost limit is an exercise in differentiating $\sqrt x$ using the definition, which you probably already know is $\dfrac1{2\sqrt x}$ .

For the leftmost limit, we make a substitution $y=\sqrt x$ . Now, if we make a slight change to $x$ by adding a small number $h$ , this propagates a similar small change in $y$ that we'll call $h'$ , so that we can set $y+h'=\sqrt{x+h}$ . Then as $h\to0$ , we see that it's also the case that $h'\to0$ (since we fix $y=\sqrt x$ ). So we can write the remaining limit as

$\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}$

which in turn is the derivative of $\tan y$ , another limit you probably already know how to compute. We'd end up with $\sec^2y$ , or $\sec^2\sqrt x$ .

So we find that

$\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}$

7 0

3 years ago

3. Express the mixed recurring decimal 15.732 in p/q form.

Alborosie

Answer

15717/999

Step-by-step explanation

n=15.732732

10n=157.32732

100n=1573.27327

1000n=15732.732732

n= 15.732732

999n=15717

999 999

4 0

3 years ago

Read 2 more answers

HELP!!!ASAP!!!!DO IN 30 MIN!!! 7TH GRADE MATH

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

big brain guess

5 0

3 years ago