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aivan3 [116]
3 years ago
12

Which of the following is best for measuring 10.0 ml water

Chemistry
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

B- beaker

Explanation:

..............

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Which statement best describes how an existing theory is often affected by the development of new technology?
grigory [225]

Answer: An existing theory is modified so that it can explain both the old and new observations.

Explanation:

4 0
3 years ago
Balance <br> Na2O+H2O → NaOH
AleksAgata [21]
Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
8 0
3 years ago
1. write the complete chemical symbol for the ion with 14 protons 15 neutrons and 18 electrons
motikmotik

Answer:

1.   Si^{-4}

2.  Co^{+2}

Explanation:

An ion is formed when an atom that is said to be neutral gains or losses electrons.

It is thought that a negative ion (anion) is produced as it gains electrons and a positive ion (cation) is formed when it loses an electron.

Atomic number is the total number of protons and electrons in a neutral atom.

From the information

Protons = 14

electron = 18

Net Charge = no of proton - no of electron

= 14 - 18 = -4

Mass number = 14 + 15 = 29

Thus, the chemical symbol = Si^{-4}

For ion with 27 proton, 32 neutrons and 25 electrons

Net charge = 27 - 25 = +2

Mass number = 27 + 32 = 59

Thus, the chemical symbol = Co^{+2}

6 0
3 years ago
What 3 gases does the flame test check for and what should you expect to see/hear?
Kazeer [188]
What of the gasses is N and the flame changes it's color from Orange to blue
7 0
4 years ago
Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati
Korvikt [17]

Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{vap}}{T_b}

where,

\Delta S = change in entropy

\Delta H_{vap} = change in enthalpy of vaporization = 40.5 kJ/mol

T_b = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{vap}}{T_b}

\Delta S=\frac{40.5kJ/mol}{352K}

\Delta S=115J/mol.K

Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K

8 0
4 years ago
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