Answer:
-- Volume of base used
--- Molarity of base
Explanation:
Given
-- Volume of acid used
--- Buret Initial reading
--- Buret Final reading
--- Molarity of the acid
Solving (a): Volume of base used (VB)
This is calculated by subtracting the initial reading from the final reading of the base buret.
i.e.
Solving (b): Molarity base (MB)
This is calculated using:
Make MB the subject
This gives:
Solving (c): <em>There is no such thing as average molarity</em>
The heat capacity of iron is 0.45J/g°C.
We calculate the heat using the equation:
ΔH = m cp ΔT
where
<span>m is the mass
ΔH is enthalphy or the heat required
cp is the heat capacity
</span><span>ΔT is the change in temperature
</span>So,
<span>ΔH = m cp ΔT = (125g) (0.45 J/g</span>°C) (75°C - 23.5<span>°C)
</span><span>ΔH = 2896.875 J
</span>
Dividing by 1000 to convert to kJ,
<span>ΔH = 2.897 kJ</span>
I believe it’s 32, I might be wrong though
You find the molar mass of NaCl first, by adding the weight of both to get 58.44g.
Then you set up the equation with what is given:
2.4mol NaCl and multiply it by 58.44g NaCl to get your answer= 140.256g
