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2 years ago

Need help on this question asap please

Chemistry

1 answer:

3241004551 [841]2 years ago

3 0

Answer:

The correct answer is - 14.

Explanation:

In the given molecular formula of the aluminum sulphite which is Al2(SO3)3, this molecular formula there different type of elements are bonded together to form this compound each element has a specific number of atoms present. This compound has three elements that are aluminum, sulfur, and oxygen and the atoms are present are:

Al = 2 atoms represented by subscript

S = 3 atoms represented as whole subscripts of sulfite

O = 9 atoms 3 inside bracket and 3 outside of bracket that multiplies.

Thus, total number of atoms are 2+3+9 = 14

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1. Circular movement around an axis

arlik [135]

it is a rotation, hope that helped:)

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2 years ago

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Burning magnesium gives us magnesium oxide. This is an example of a reaction.

frez [133]

Answer: -

Oxidation, Oxygen

Explanation: -

Burning of magnesium gives us magnesium oxide.

The chemical symbol of magnesium is Mg.

The chemical symbol of magnesium oxide is MgO.

So, the balanced chemical equation is

2Mg + O2 – 2 MgO.

We see that the element added is O Oxygen. So, the reaction is oxidation.

In oxidation always, oxygen is the common element involved in all chemical reactions of this kind.

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3 years ago

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A buffer solution contains 0.240 M ammonium chloride and 0.499 M ammonia. If 0.0565 moles of perchloric acid are added to 250 mL

snow_lady [41]

Answer:

The pH of the resulting solution is 9.02.

Explanation:

The initial pH of the buffer solution can be found using the Henderson-Hasselbalch equation:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.240}{0.499}) = 4.43$

$pH = 14 - pOH = 14 - 4.43 = 9.57$

Now, the perchloric acid added will react with ammonia:

$n_{NH_{3}} = 0.499moles/L*0.250 L - 0.0565 moles = 0.0683 moles$

Also, the moles of ammonium chloride will increase in the same quantity according to the following reaction:

NH₃ + H₃O⁺ ⇄ NH₄⁺ + H₂O

$n_{NH_{4}Cl} = 0.240 moles/L*0.250L + 0.0565 moles = 0.1165 moles$

Finally, we can calculate the pH of the resulting solution:

$pOH = pKb + log(\frac{[NH_{4}Cl]}{[NH_{3}]})$

$pOH = -log(1.78\cdot 10^{-5}) + log(\frac{0.1165 moles/0.250 L}{0.0683 moles/0.250 L}) = 4.98$

$pH = 14 - 4.98 = 9.02$

Therefore, the pH of the resulting solution is 9.02.

I hope it helps you!

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3 years ago

Which statement describes the charge of an

qwelly [4]

I think that you didn't copy the answers correctly, because 1 and 2 are the same, and 3 and 4 are also the same here.
Anyways, the answer which is correct is that an electron has a charge of -1, and a proton has a charge of +1.
Electrons are negatively charged, whereas protons are positively charged. Neutrons are neutral.

6 0

2 years ago

Nitroglycerin is a dangerous powerful explosive that violently decomposes when it is shaken or dropped. The Swedish chemist Alfr

Ganezh [65]

Answer:

a. $4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)$

b. 146.0 g

Explanation:

Question 1 (a). Just as the problem states, liquid nitroglycerin decomposes into nitrogen gas $N_2$ , oxygen gas $O_2$ , water vapor $H_2O$ and carbon dioxide $CO_2$ . Let's write the decomposition of nitroglycerin into these 4 components:

$C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + CO_2 (g)$

Now we need to balance the equation. Firstly, notice we have 3 carbon atoms on the left and 1 on the right, so let's multiply carbon dioxide by 3:

$C_3H_5N_3O_9 (l)\rightarrow N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)$

Now, we have 3 nitrogen atoms on the left and 2 on the right, so let's multiply nitrogen on the right by $\frac{3}{2}$ :

$C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + H_2O (g) + 3 CO_2 (g)$

We have 5 hydrogen atoms on the left, 2 on the right, so let's multiply the right-hand side by $\frac{5}{2}$ :

$C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)$

Finally, count the oxygen atoms. We have a total of 9 on the left. On the right we have (excluding oxygen molecule):

$\frac{5}{2} + 6 = 8.5$

This leaves $9 - 8.5 = 0.5 = \frac{1}{2}$ of oxygen. Since oxygen is diatomic, we need to take one fourth of it to get one half in total:

$C_3H_5N_3O_9 (l)\rightarrow \frac{3}{2}N_2 (g) + \frac{1}{4} O_2 (g) + \frac{5}{2} H_2O (g) + 3 CO_2 (g)$

To make it look neater without fractional coefficients, multiply both sides by 4:

$4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)$

Question 2 (b). Now we can make use of the balanced chemical equation and apply it for the context of this separate problem. We're given the following variables:

$V_{CO_2} = 41.0 L$

$T = -14.0^oC + 273.15 K = 259.15 K$

$p = 1 atm$

Firstly, we may find moles of carbon dioxide produced using the ideal gas law $pV = nRT$ .

Rearranging for moles, that is, dividing both sides by RT (here R is the ideal gas law constant):

$n_{CO_2} = \frac{pV_{CO_2}}{RT} = \frac{1 atm\cdot 41.0 L}{0.08206 \frac{L atm}{mol K}\cdot 259.15 K} = 1.928 mol$

According to the stoichiometry of the balanced chemical equation:

$4 C_3H_5N_3O_9 (l)\rightarrow 6N_2 (g) + O_2 (g) + 10 H_2O (g) + 12 CO_2 (g)$

4 moles of nitroglycerin (ng) produce 12 moles of carbon dioxide. From here we can find moles o nitroglycerin knowing that:

$\frac{n_{ng}}{4} = \frac{n_{CO_2}}{12} \therefore n_{ng} = \frac{4}{12}n_{CO_2} = \frac{1}{3}\cdot 1.928 mol = 0.6427 mol$

Multiplying the number of moles of nitroglycerin by its molar mass will yield the mass of nitroglycerin decomposed:

$m_{ng} = n_{ng}\cdot M_{ng} = 0.6427 mol\cdot 227.09 g/mol = 146.0 g$

3 0

3 years ago