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ivann1987 [24]
3 years ago
13

I really need some help and explaining with the Heat of Combustion Lab.

Chemistry
1 answer:
Nataly_w [17]3 years ago
6 0
<span>Combustion means the elements or compound can be burned, but burning which is a chemical process requires oxygen; combustion reaction typically takes place in the presence of air. The combustion of methane is as follows: CH4(g) + 2 O2(g) -> CO2(g)+ 2 H2O(g) + energy One mole of gaseous methane reacts with two oxygen molecules to form a carbon dioxide molecule, and two water molecules which is given off as water vapor. The reaction involves the release of heat.</span>
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Approximately how many moles of chlorine make up 1.79 × 1023 atoms of chlorine?
e-lub [12.9K]
1.2*10^24# atoms of chlorine

Explanation:
Chlorine gas (#Cl_2#) has two atoms of elemental chlorine in a molecule, so:
#1# mol of #Cl_2# have #6*10^23# molecules of #Cl_2#
#1# molecule of #Cl_2# have #2# atoms per molucule
Then #2*6*10^23 = 1.2*10^24# atoms of chlorine in a mol of chlorine gas
6 0
3 years ago
When the metal was placed in the calorimeter its
guajiro [1.7K]

Answer:

Exam 3 Material

Homework Page Without Visible Answers

This page has all of the required homework for the material covered in the third exam of the first semester of General Chemistry. The textbook associated with this homework is CHEMISTRY The Central Science by Brown, LeMay, et.al. The last edition I required students to buy was the 12th edition (CHEMISTRY The Central Science, 12th ed. by Brown, LeMay, Bursten, Murphy and Woodward), but any edition of this text will do for this course.

Note: You are expected to go to the end of chapter problems in your textbook, find similar questions, and work out those problems as well. This is just the required list of problems for quiz purposes. You should also study the Exercises within the chapters. The exercises are worked out examples of the questions at the back of the chapter. The study guide also has worked out examples.

These are bare-bones questions. The textbook questions will have additional information that may be useful and that connects the problems to real life applications, many of them in biology.

Explanation:

5 0
2 years ago
Read 2 more answers
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
3 years ago
Anouk does 150 J of work using a hammer to pull a nail out of a piece of wood, and the hammer does 105 J of work on the nail. Wh
astraxan [27]
The efficiency of any machine is given by:

efficiency = output obtained / input given

Substituting the values,
Efficiency = 105 / 150
Efficiency = 0.7

Converting this to a percentage, the efficiency of the hammer is 70%.
This is a fairly high efficiency, and this is due to the fact that the hammer is a simpler machine. The more complex a machine is, the greater are the losses in it due to friction, meaning there is a lower efficiency.
6 0
3 years ago
Read 2 more answers
Consider two different ions. The anion has a valence of -2. The cation has a valence of +2. The two ions are separated by a dist
strojnjashka [21]

Answer:

Force of attraction = 35.96 \times 10^{27}N

Explanation:

Given: charge on anion = -2

Charge on cation = +2

Distance = 1 nm = 10^{-9} m

To calculate: Force of attraction.

Solution: The force of attraction is calculated by using equation,

F = \dfrac{k \times q_1 q_2}{ \r^2} ---(1)

where, q represents the charge and the subscripts 1 and 2 represents cation and anion.

k = 8.99 \times 10^9 \ Nm^{2}C^{-2}

F = force of attraction

r = distance between ions.

Substituting all the values in the equation (1) the equation becomes

F = \dfrac{8.99 \times 10^9 \times 2 \times 2}{ \left ( 10^-9 \right )^2 }

Force of attraction = 35.96 \times 10^{27}N

6 0
3 years ago
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