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3 years ago

La longitud de una varilla es de 12 pulgadas y la de otra varilla es de

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

Hi how are you doing today Jasmine

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Find the exact value of the trigonometric function of theta from the given information. cosine thetaequalsnegative StartFraction

Iteru [2.4K]

Is it a multiple choise?

7 0

3 years ago

Generate an equivalent algebraic expression by combining like terms.<br><br> 2x-6y+2x^2-21-4y+4x-x^2

Vlad1618 [11]

I’m pretty sure it’s

6x-10y+x^2-21

Unless I read it wrong then sorry

3 0

3 years ago

How do I differentiate this?

disa [49]

Answer:

$\frac{8}{\left(-x+2\right)^2}$ & $x = 1, x = 3$

Step-by-step explanation:

I'm sure you are familiar with the product rule,

If y = u*v => dy/dx = u * dv/dx + v * dy/dx <----- product rule

In this case:

$u=3x+2,\:v=\left(2-x\right)^{-1},\\=>\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

Now remember the sum rule:

$\frac{d}{dx}\left(3x+2\right) = \frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(2\right),\\\frac{d}{dx}\left(3x\right) = 3,\\\frac{d}{dx}\left(2\right) = 0\\\frac{d}{dx}\left(3x+2\right) = 3$

For this second bit we apply the chain rule:

$\frac{d}{dx}\left(\left(2-x\right)^{-1}\right) = -\frac{1}{\left(2-x\right)^2}\frac{d}{dx}\left(2-x\right),\\\frac{d}{dx}\left(2-x\right) = -1,\\\\=> -\frac{1}{\left(2-x\right)^2}\left(-1\right)\\=> \frac{1}{\left(2-x\right)^2}$

If we substitute these values back into the expression... $\frac{d}{dx}\left(3x+2\right)\left(2-x\right)^{-1}+\frac{d}{dx}\left(\left(2-x\right)^{-1}\right)\left(3x+2\right)$

...we get the following:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)$

The rest is just pure simplification:

$3\left(2-x\right)^{-1}+\frac{1}{\left(2-x\right)^2}\left(3x+2\right)\\= \frac{3}{-x+2}+\frac{3x+2}{\left(-x+2\right)^2}\\= \frac{3\left(-x+2\right)}{\left(-x+2\right)^2}+\frac{3x+2}{\left(-x+2\right)^2}\\\\= \frac{3\left(-x+2\right)+3x+2}{\left(-x+2\right)^2}\\\\= \frac{8}{\left(-x+2\right)^2}$

Now let's equate this to equal 8 for the second bit and solve for x:

$\frac{8}{\left(-x+2\right)^2}=8,\\\frac{8}{\left(-x+2\right)^2}\left(-x+2\right)^2=8\left(-x+2\right)^2,\\8=8\left(-x+2\right)^2,\\\left(-x+2\right)^2=1,\\x = 1, x = 3$

4 0

3 years ago

Can someone please help me with these two questions?

Dima020 [189]

the first picture you have to use B X L X H ( base, length and height) and i got 1728 mm^3

for the second one, you have to use the formula L X H ( P+ Q/2) ( length times height times the product of the base width plus the top width divided by 2 and i got the answer of 196 m^3.

i hope this helps :)

8 0

3 years ago

Help please will mark Brainlyest plz help quickly

Helga [31]

Answer: 28*63

Step-by-step explanation:

- If first you want the answer, you must divide and then you would get 63.

- Then you take 63 and multiply 28 and you'll get 1,764

Hope I was able to help.

(For question 27)

8 0

3 years ago