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Stolb23 [73]
3 years ago
14

Can someone help me? Please and thank you! <3

Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer:

I think it would be 40?

Step-by-step explanation:

I think 40 because if I recall correctly, to find the range you must subtract the max from the min, the max being 100 and the min being 60 in this case.

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Your answer is (B). :)
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kicyunya [14]

The two numbers in between which the lower quartile value given by the attached boxplot falls are 1.5 and 2.5 respectively.

  • The lower quartile means the 25th percentile or lower \frac{1}{4}th of the distribution

  • From a boxplot, the lower quartile is the point marked by the starting point of the box.

  • The Lower quartile of the distribution represented by the boxplot is 2

  • The values which bounds the lower quartile value to the left and right are 1.5 and 2.5 respectively.

Therefore, two numbers in between which the lower quartile value falls are 1.5 and 2.5

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3 years ago
PLS HELP I WILL GIVE BRAINLY
SCORPION-xisa [38]

Answer:

the answer to the problem is 2.25. i think k=3 if x=3/4 and y=2.25

Step-by-step explanation:

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A farmer is building a fence to enclose a rectangular area against an existing wall, shown in the figure below.
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The most appropriate choice for maxima and minima of a function will be given by

Rectangle of length 72 feet and breadth 36 feet has largest area

What is maxima and minima?

Maxima of function f(x) is the maximum value of the function and minima of function f(x) is the minimum value of the function.

Here,

Let the length be x feet and breadth be y feet

The farmer has 144 feet of fencing

Three of the sides will require fencing and the fourth wall already exists.

So,

x + y + y =1 44

x + 2y = 144

Area of rectangle(A) = xy ft^2

                               = (144 - 2y)y

                               = 144y - 2y^2

\frac{dA}{dy} = \frac{d}{dy}(144y - 2y^2)

     = 144 - 2\times 2y^{2-1}\\144 - 4y

For largest area,

\frac{dA}{dy} = 0

144 - 4y = 0 \\4y = 144\\y = \frac{144}{4}\\y = 36

\frac{d^2A}{dy^2} = \frac{d}{dy}(144 - 4y)\\=0-4\\=-4 < 0

Hence area is maximum

For largest area, y = 36 feet

x = 144 - 2\times 36\\x = 144-72\\

x = 72 feet

So length of rectangle is 72 feet, breadth of rectangle is 36 feet

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What does rail me meani need to know​
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the word “rail” means rough intercourse without any emotional attachment.

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