Angle A is three times the size of angle B.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

4 0

First, let's declare our variables

B = x+2

A = 3(x+2)

Now, let's create our expression.

A + B = 128

Plug in the values for A and B

x+2 + 3(x+2) = 128

We need to solve for x. Start off by simplifying the left side.

x+2 + 3x + 6 = 128

Combine like terms.

4x + 8 = 128

Subtract 8 from both sides.

4x = 120

Divide both sides by 4

x = 30

B = x+2 = 30 + 2 = 32 degrees

A = 3(x+2) = 3(30+2) = 3(32) = 96 degrees

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5 0

3 years ago

Read 2 more answers

PLEASE HELP!! if sec x=5/3 what is the value of b? NL=20 LM=3b angle of L is x degrees.

Readme [11.4K]

Answer:

a. b=4

Step-by-step explanation:

$\sec \theta =\dfrac{1}{\cos \theta} = \dfrac{Hypotenuse}{Adjacent}$

From the attached triangle drawn below:

NL=20, LM=3b, $\angle L=x^\circ$

$\sec x =\dfrac{20}{3b}$

Since we are told that:

$\sec x =\dfrac{5}{3}\\$Then:\\\dfrac{20}{3b} =\dfrac{5}{3}\\$Cross multiply\\5 \times 3b =20 \times 3\\15b=60\\$Divide both sides by 15\\15b \div 15 =60 \div 15\\b=4$