Question

Question 17 of 25

Answer 1

Answer:

The speed of the wave as it travelled through the brass bell is;

B. 4,700 m/s

Explanation:

The given parameters are;

The wavelength of the sound wave produced from the brass bell, $\lambda _{(air)}$  = 3.5 m

The wavelength of the wave in the brass bell, $\lambda _{(brass \ bell)}$  = 47 m

The frequency of the wave in the brass bell, f = 100 Hz

The given equation for wave speed, v = f × λ

Therefore, the speed of the wave as it travelled through the brass bell, $v _{(brass \ bell)}$, is given as follows;

$v _{(brass \ bell)}$ = f × $\lambda _{(brass \ bell)}$ = 100 Hz × 47 m = 4,700 m/s  

The speed of the wave as it travelled through the brass bell =  $v _{(brass \ bell)}$ = 4,700 m/s

Answer 2

Answer:

B.) 4700 m/s

Explanation: