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IRINA_888 [86]
3 years ago
15

Two forces Upper FSubscript Upper A Baseline Overscript right-arrow EndScripts and Upper FSubscript Upper B Baseline Overscript

right-arrow EndScripts are applied to an object whose mass is 10.6 kg. The larger force is Upper FSubscript Upper A Baseline Overscript right-arrow EndScripts. When both forces point due east, the object's acceleration has a magnitude of 0.554 m/s2. However, when Upper FSubscript Upper A Baseline Overscript right-arrow EndScripts points due east and Upper FSubscript Upper B Baseline Overscript right-arrow EndScripts points due west, the acceleration is 0.313 m/s2, due east. Find (a) the magnitude of Upper FSubscript Upper A Baseline Overscript right-arrow EndScripts and (b) the magnitude of Upper FSubscript Upper B Baseline Overscript right-arrow EndScripts.
Physics
1 answer:
Pavel [41]3 years ago
5 0

Answer:

Part a)

F_A = 4.59 N

Part B)

F_B = 1.28 N

Explanation:

As we know that when both the forces are acting on the object in same direction then we will have

F_A + F_B = ma

as we know that

a = 0.554 m/s^2

m = 10.6 kg

now we will have

F_A + F_B = 10.6(0.554)

F_A + F_B = 5.87 N

Now two forces are in opposite direction then we have

F_A - F_B = 10.6(0.313)

F_A - F_B = 3.32 N

Part A)

Now we will have from above two equation

F_A = 4.59 N

Part B)

Similarly for other force we have

F_B = 1.28 N

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Two water jets are emerging from a vessel at a height of 50 centimeters and 100 centimeters. If their horizontal velocities at t
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For t1:

t1 = square root of 2h1 / g = square root of 2 * 0.5 / 9.8 = 0.319 sec

For t2:

t2 = sqaure root of 2h2 / g = square root of 2 * 1.0 / 9.8 = 0.451 sec

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Read 2 more answers
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