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Luba_88 [7]
3 years ago
10

Two resistors are to be combined to form an equivalent resistance of 1000 Ω. The resistors are taken from available stock on han

d as acquired over the years. Readily available are two common resistors rated at 500 ± 50 Ω and two common resistors rated at 2000 ± 100 Ω. (a) Calculate the uncertainties for both combinations. (b) What combination of resistors (series or parallel) would provide the smaller uncertainty in an equivalent 1000 Ω resistance?

Physics
1 answer:
LenKa [72]3 years ago
5 0

Answer:

Even though each of 2000 ohms resistor has twice the uncertainty of a 500 ohms resistor, the parallel circuit has half the uncertainty of the series circuit

Thus, the PARALLEL CIRCUIT would be more accurate

Explanation:

Check attachment for solution

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PLEASE HELP!! ITS URGENT!!!​
Natasha2012 [34]

Answer:

F = 800 [N]

Explanation:

To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.

We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.

ΣPbefore = ΣPafter

(m_{1}*v_{1}) - F*t = (m_{1}*v_{2})

where:

m₁ = mass of the hammer = 0.15 [m/s]

v₁ = velocity of the hammer = 8 [m/s]

F = force [N] (units of Newtons)

t = time = 0.0015 [s]

v₂ = velocity of the hammer after the impact = 0

(0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N]

Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.

6 0
3 years ago
No matter what values of m and k you used for the spring, what is the ratio of the period to k m.
Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to \sqrt{\dfrac{m}{k} }.

Response:

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

<u />

<h3>How is the value of the ratio of the period to \sqrt{\dfrac{m}{k} } calculated?</h3>

Given:

The relationship between the period, <em>T</em>, the spring constant <em>k</em>, and the

mass attached to the spring <em>m</em> is presented as follows;

T =  \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}

Therefore, the fraction of of the period to \sqrt{\dfrac{m}{k} }, is given as follows;

\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi

2·π ≈ 6.23

Therefore;

T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1

Which gives;

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0
3 years ago
When a positively charged rod is used to charge a second rod by induction, the induced charge is?
igor_vitrenko [27]
The positive rod will induce a negative charge on the side of the other rod it is closest to.
4 0
3 years ago
Which characteristics belong to Whittaker’s classification system? Select two options.
Lana71 [14]

Answer:

Five kingdoms & Seven levels

Explanation:

Robert H. Whittaker proposed five kingdom classical system for living organisms in 1969. These were: Kingdom Monera, Kingdom Protista, Kingdom Fungi, Kingdom Animalia, and Kingdom Plantae. His work was the improvement of earlier work conducted by Carl Linnaeus who proposed three kingdom classification system (Animalia, Plantae, and Protista).

Whittaker's system further categorized each kingdom to seven levels. These were: Kingdom → Phylum  →  Class  →   Order  →   Family →   Genus  →   Species. This categorization was based on similarities in organisms at different levels.

PS: The scientific name of each organism is the combination of genus and family name.

4 0
3 years ago
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Which of the following terms refers to the amount of heat needed to change 1 kg of a substance from a liquid to a gas at its boi
Nataly [62]
It's B I thinkkkkkkkk
8 0
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