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Darina [25.2K]
3 years ago
14

Please help asap oiuytyghjkjhugytfhjkl

Mathematics
2 answers:
Alika [10]3 years ago
7 0

Answer:

112

Step-by-step explanation:

correct me if im wrong.

I got this from doing 30 percent out of 160

160×0.30

160-48=112

zysi [14]3 years ago
4 0

Answer:

112

Step-by-step explanation:

30%*160=48

160-48=112

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3 years ago
Read 2 more answers
For what real value of $v$ is $\frac{-21-\sqrt{301}}{10}$ a root of $5x^2+21x+v$?
Degger [83]

Answer:

v = 7

is the value for which

x = (-21 - √301)/10

is a solution to the quadratic equation

5x² + 21x + v = 0

Step-by-step explanation:

Given that

x = (-21 - √301)/10 .....................(1)

is a root of the quadratic equation

5x² + 21x + v = 0 ........................(2)

We want to find the value of v foe which the equation is true.

Consider the quadratic formula

x = [-b ± √(b² - 4av)]/2a ..................(3)

Comparing (3) with (2), notice that

b = 21

2a = 10

=> a = 10/2 = 5

and

b² - 4av = 301

=> 21² - 4(5)v = 301

-20v = 301 - 441

-20v = -140

v = -140/(-20)

v = 7

That is a = 5, b = 21, and v = 7

The equation is then

5x² + 21x + 7 = 0

6 0
3 years ago
•How do the solutions to an equation relate to the graph of the equation?
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3 years ago
Whats the definition of the a square root ?
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3 years ago
What is the equation of a line perpendicular to why=2x-6 that passes through (5,4)
almond37 [142]

Answer:

y = ½(13- x)

Step-by-step explanation:

Step 1. Find the<em> slope (m₁) of the original line </em>

The equation for the original line is

      y = 2x - 6

slope = m₁ = 2

Step 2. Find the <em>slope (m₂) of the perpendicular line </em>

m₂ = -1/m₁     Substitute the value of m₁

m₂ = -1/2

Step 3. Find the <em>equation for the perpendicular line</em>

y = mx + b     Substitute the value of m₂

y = -½x + b

The line passes through (5, 4).  

4 = -½(5) + b     Add 5/2 to each side

4 = -5/2 + b     Add 2 to each side

b = 13/2  

y = -½x + 13/2

y = ½(13 – x)  

In the image, below, the red line is the graph of your original equation.

The blue line passing through (5, 4) is the perpendicular line.

4 0
3 years ago
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