<span>Draw the Lewis structure. Bromine has 3 bonds and two lone pairs for a trigonal bipyramidal electron geometry and an sp^3d hybridization. Fluorine is peripheral it does not require hybridization, but we often consider it to be hybridized too - it has 1 bond and 3 lone pairs for sp^3 hybridization. So the sigma bonds come from an overlap of an sp^3d orbital on Br with an sp^3 orbital on F. If you don't consider the F to be hybridized the overlap would have to be to a p orbital on the F</span>
The bathtub of water would melt the most ice because it has a larger area
Answer:
22.01J/Kmol
Explanation:
The parameters given in this question are;
Enthalpy (H) = 6.01 kJ/mol.
Number of moles = 1
Entropy change (S) = ?
The formular relationship between entropy and enthalpy is given as;
ΔS=ΔH/T
Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)
ΔS = 6.01/273
ΔS = 0.0220kJ/Kmol
ΔS = 0.02201 * 1000 = 22.01J/Kmol
The full question can be seen below:
The decomposition of 
is represented by the equation above.
A student monitored the decomposition of a 1.0 L sample of 
at a constant temperature of 300K and recorded the concentration of 
as function of time. The results are given in the table below:
Time (s)
0 2.7
200 2.1
400 1.7
600 1.4
The 
produced from the decomposition of the 1.0 L sample of is collected in a previously evacuated 10.0 L flask at 300 K. What is the approximate pressure in the flask after 400 s?
(For estimation purpose, assume that 1.0 mole of gas in 1.0 L exerts a pressure of 24 atm at 300 K).
Answer:
1.2 atm
Explanation:
Considering all assumptions as stated above;
Initial 2.7 mole --- ---
Change -1.0 --- 
Equilibrium 1.7 mole --- 0.5 mole
To determine the concentration of O₂; we need to convert the moles to concentration for O₂ = 
= 
= 0.05 
Thus, based on the assumption that "1.0 mole of gas in 1.0 L exerts a pressure of 24 atm"
∴ 0.05 will give rise to = 0.05 × 24
= 1.2 atm
