Answer:
ch3c(ch3)(oh)ch3
Explanation:
that should be the answer
Answer:
2.1 M is the molarity of the HCl solution.
Explanation:

Molarity of HCl solution = 
Volume of HCl solution = 
Ionizable hydrogen ions in HCl = 
Molarity of NaOH solution = 
Volume of NaOH solution = 
Ionizable hydroxide ions in NaOH = 
(neutralization )


2.1 M is the molarity of the HCl solution.
Answer: There are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
Explanation:
Given: Mass of silver = 1.4 g
Number of moles is the mass of substance divided by its molar mass.
As molar mass of silver is 107.86 g/mol. Therefore, moles of silver are calculated as follows.

Thus, we can conclude that there are 0.0129 moles of silver present in 1.4 grams of silver (Ag).
Molarity is moles per liter. Therefore you must covert grams->moles by dividing 9.82 by the molar mass of lead IV nitrate. Then convert mL->L. Once you have those two numbers you can plug them into the formula Molarity = mol/L.
Answer : The weight of water is 9 g
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number
of particles.
To calculate the number of moles, we use the equation:

1 mole of water
weighs = 18 g
0.5 moles of water
weighs = 
Thus the weight of water is 9 g