Question

Equation of the line that passes through the point (-2, 0) and has a slope

Answer 1

Answer:

The equation of the line that passes through the point (-2, 0) and has a slope -2 is:

•  $y = -2x - 4$

The graph of the line equation $y = -2x - 4$ is also attached.

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

• m is the slope

• b is the y-intercept

Given that the equation of the line that passes through the point (-2, 0) and has a slope of -2.

so we have

• slope m = -2

• point (-2, 0)

The first step we need to do is to determine the y-intercept of the line.

so substituting m = -2 and (-2, 0) in the slope-intercept form of the line equation to determine the y-intercept b

$y = mx + b$

$0 = -2(-2) + b$        ∵ (x, y) = (-2, 0)

$0 = 4 + b$

$b = -4$

Thus, the y-intercept b of the line is: b = -4

The second step is to substitute b = -4 and m = -2 in the slope-intercept form of the line equation

$y = mx + b$

$y = -2x + (-4)$

$y = -2x - 4$

Therefore, the equation of the line that passes through the point (-2, 0) and has a slope -2 is:

•  $y = -2x - 4$

The graph of the line equation $y = -2x - 4$ is also attached.